求系列 3, 11, 31, 69, 的第 n 项。 . . . .

给定一个整数N ，任务是找到序列的第 N 项

3, 11, 31, 69, . . . . . till Nth term.

例子：

Input: N = 3 
Output: 31

Input: N = 6
Output: 223

方法：

从给定的系列中，找到第 N 项的公式 -

1st term = 1 ^ 3 + (1 + 1) = 3

2nd term = 2 ^ 3 + (2 + 1) = 11

3rd term = 3 ^ 3 + (3 + 1) = 31

4th term = 4 ^ 3 + (4 + 1) = 69

.

.

Nth term = n  ^ 3 + (n + 1)

给定系列的第 N 项可以概括为-

T_N = n  ^ 3 + (n + 1)

插图：

Input: N = 5
Output: 131
Explanation:
T_N = n  ^ 3 + (n + 1)   
     = 5 ^ 3 + (5 + 1)    
     = 131

以下是上述方法的实现 -

C++

// C++ program to find nth
// term of the series
#include 
using namespace std;
 
// Function to return nth
// term of the series
int find_nth_Term(int n)
{
    return n * n * n + (n + 1);
}
 
// Driver code
int main()
{
    // Find given nth term
    int n = 5;
 
    // Function call
    cout << find_nth_Term(n) << endl;
    return 0;
}

Java

// Java code for the above approach
import java.io.*;
 
class GFG {
 
  // Function to return nth
  // term of the series
  static int find_nth_Term(int n)
  {
    return n * n * n + (n + 1);
  }
 
  // Driver code
  public static void main(String[] args)
  {
 
    // Find given nth term
    int n = 5;
 
    // Function call
    System.out.println(find_nth_Term(n));
  }
}
 
// This code is contributed by Potta Lokesh

Python

# Python program to find nth
# term of the series
 
# Function to return nth
# term of the series
def find_nth_Term(n):
     
    return n * n * n + (n + 1)
 
# Driver code
 
# Find given nth term
n = 5
 
# Function call
print(find_nth_Term(n))
 
# This code is contributed by Samim Hossain Mondal.

C#

// C# program to find nth
// term of the series
using System;
class GFG
{
 
  // Function to return nth
  // term of the series
  static int find_nth_Term(int n)
  {
    return n * n * n + (n + 1);
  }
 
  // Driver code
  public static int Main()
  {
 
    // Find given nth term
    int n = 5;
 
    // Function call
    Console.WriteLine(find_nth_Term(n));
    return 0;
  }
}
 
// This code is contributed by Taranpreet

Javascript

// Javascript program to find nth
// term of the series
 
// Function to return nth
// term of the series
function find_nth_Term(n)
{
    return n * n * n + (n + 1);
}
 
// Driver code
// Find given nth term
let n = 5;
 
// Function call
document.write(find_nth_Term(n))
 
// This code is contributed by gfgking.

输出

131

时间复杂度： O(1)
辅助空间： O(1)