求一个长轴为 50 个单位,短轴为 20 个单位的水平椭圆方程
圆锥截面也称为圆锥曲线,是在平面与圆锥相交时形成的。这些部分的形状取决于交叉点发生的角度。因此有四种类型的圆锥曲线,即圆、椭圆、抛物线和双曲线。这些形状中的每一个都有自己的属性和数学方程式。下面讨论椭圆。
椭圆
椭圆是一种圆锥截面,当平面以 0 到 90 度之间的角度与圆锥相交时形成。结果,它概括了一个圆,这是一种特殊的椭圆,具有相同的两个焦点。
椭圆的偏心率 e 是一个范围从 e=0 到 e=1 的量,它显示了它沿每个轴的拉长程度。椭圆有两个轴,分别称为长轴和短轴。在水平椭圆的情况下,沿 x 轴的轴称为长轴,沿 y 轴的轴称为短轴。
椭圆方程
以原点为中心的椭圆方程的标准形式如下:
where a and b are the semi-major and minor axes respectively.
需要记住的是,如果 a > b,那么我们手头有一个水平椭圆。否则,如果 a < b,则它是一个垂直椭圆。
求一个长轴为 50 个单位,短轴为 20 个单位的水平椭圆方程。
解决方案:
The standard form of equation of a horizontal ellipse with its center at the origin is , a > b.
Given: Length of major axis = 2a = 50 units
⇒ a = 50/2 = 25 units
Length of minor axis = 2b = 25 units
⇒ b = 20/2 = 10 units
Substituting the values in the equation, we have:
类似问题
问题 1. 为一个长轴为 60 个单位,短轴为 20 个单位的水平椭圆做一个方程?
解决方案:
The standard form of equation of a horizontal ellipse with its center at the origin is , a > b.
Given: Length of major axis = 2a = 60 units
⇒ a = 60/2 = 30 units
Length of minor axis = 2b = 20 units
⇒ b = 20/2 = 10 units
Substituting the values in the equation, we have:
问题 2. 为一个长轴为 30 个单位,短轴为 10 个单位的水平椭圆做一个方程?
解决方案:
The standard form of equation of a horizontal ellipse with its center at the origin is , a > b.
Given: Length of major axis = 2a = 30 units
⇒ a = 30/2 = 15 units
Length of minor axis = 2b = 10 units
⇒ b = 20/2 = 5 units
Substituting the values in the equation, we have:
问题 3. 为一个长轴为 70 个单位,短轴为 40 个单位的水平椭圆做一个方程?
解决方案:
The standard form of equation of a horizontal ellipse with its center at the origin is , a > b.
Given: Length of major axis = 2a = 70 units
⇒ a = 70/2 = 35 units
Length of minor axis = 2b = 40 units
⇒ b = 40/2 = 20 units
Substituting the values in the equation, we have:
问题 4. 为一个长轴为 100 个单位,短轴为 20 个单位的水平椭圆做一个方程?
解决方案:
The standard form of equation of a horizontal ellipse with its center at the origin is , a > b.
Given: Length of major axis = 2a = 100 units
⇒ a = 100/2 = 50 units
Length of minor axis = 2b = 20 units
⇒ b = 20/2 = 10 units
Substituting the values in the equation, we have:
问题 5. 为一个长轴为 42 个单位,短轴为 6 个单位的水平椭圆做一个方程?
解决方案:
The standard form of equation of a horizontal ellipse with its center at the origin is , a > b.
Given: Length of major axis = 2a = 42 units
⇒ a = 42/2 = 21 units
Length of minor axis = 2b = 6 units
⇒ b = 6/2 = 3 units
Substituting the values in the equation, we have: