如果一个数字超过另一个数字 5 并且数字的总和为 1,则找到数字
数字系统或数字系统被定义为表示数字和图形的基本系统。它是一种在算术和代数结构中表示数字的独特方式。在各种算术值中,数字适用于进行各种算术运算,如加法、减法、乘法等,这些运算适用于日常生活中的计算目的。数字值由数字、它在数字中的位置值以及数字系统的基数确定。它也被称为数字,是用于计数、测量、标记和测量基本量的数学值。
这些是用于测量或计算数量的数学值或数字。它用数字表示为 3、6、9 等。数字的一些例子是整数、整数、自然数、有理数和无理数等。
一个数比另一个数多 5。这些数的总和是 1。这些数是多少?
解决方案:
Let one number be x
Another number will be, x + 5
Sum of these number are 1,
x + x + 5 = 1
2x + 5 = 1
2x = 1 – 5
2x = -4
x = -2
Then, x + 5 will be,
= x + 5
= -2 + 5
= 3
So, the numbers are -2 and 3
类似问题
问题 1:一个数比另一个数多 7。这些数的和是 1。这些数是多少?
解决方案:
Let one number be x
Another number will be, x + 7
Sum of these number are 1,
x + x + 7 = 1
2x + 7 = 1
2x = 1-7
2x = -6
x = -3
Then, x + 7 will be,
= x + 7
= -3 + 7
= 4
So, the numbers are -3 and 4
问题 2:一个数比另一个数多 4。这些数的和是 8。这些数是多少?
解决方案:
Let one number be x
Another number will be, x + 4
Sum of these number are 8,
x + x + 4 = 8
2x + 4 = 8
2x = 8 – 4
2x = 4
x = 2
Then, x + 4 will be,
= x + 4
= 2 + 4
= 6
So, the numbers are 2 and 6
问题 3:一个数减去另一个数 5。这些数的总和是 9。这些数是多少?
解决方案:
Let one number be x
Another number will be, x – 5
Sum of these number are 9,
x + x – 5 = 9
2x – 5 = 9
2x = 9 + 5
2x = 14
x = 7
Then, x – 5 will be,
= x – 5
= 7 – 5
= 2
So, the numbers are 7 and 2
问题 4:一个数减去另一个数 4。这些数的和是 8。这些数是多少?
解决方案:
Let one number be x
Another number will be, x – 4
Sum of these number are 8,
x + x – 4 = 8
2x – 4 = 8
2x = 8 + 4
2x = 12
x = 6
Then, x – 4 will be,
= x – 4
= 6 – 4
= 2
So, the numbers are 6 and 2
问题 5:一个数比另一个数多 4。这些数的和是 10。这些数是多少?
解决方案:
Let one number be x
Another number will be, x + 4
Sum of these number are 10
x + x + 4 = 10
2x + 4 = 10
2x = 10 – 4
2x = 6
x = 3
Then, x + 4 will be,
= x + 4
= 3 + 4
Other number is = 7
So, the numbers are 3 and 7
问题 6:一个数是另一个数的两倍,并且超过 5。这些数的总和是 8。这些数是多少?
解决方案:
Let one number be x
Another number will be, 2x + 5
Sum of these number are 8,
x + 2x + 5 = 8
3x + 5 = 8
3x = 8 – 5
3x = 3
x = 1
Then, 2x + 5 will be,
= 2x + 5
= 2 (1)+ 5
= 7
So, the numbers are 1 and 7
问题 7:一个数是另一个数的两倍,并且超过 5。这些数的和是 11。这些数是多少?
解决方案:
Let one number be x
Another number will be, 2x + 5
Sum of these number are 11,
x + 2x+ 5 = 11
3x + 5 = 11
3x = 11 – 5
3x = 6
x = 2
Then, 2x + 5 will be,
= 2x + 5
= 2 (2)+ 5
= 9
So, the numbers are 2 and 9