通过使用给定数量的一个交换操作可能的最大偶数
给定一个字符串形式的奇数,任务是从给定的数字中产生最大的偶数,并且您只能进行一次交换操作。
例子 :
Input : 1235785
Output :1535782
Swap 2 and 5.
Input : 536425
Output : 536524
Swap 4 and 5 to make the largest even number.
- 在最后一个索引处找到小于或等于奇数的第一个偶数。
- 如果找到,交换两个值。否则与字符串中的最后一个偶数值交换。
- 如果不可能,打印给定的字符串。
C++
// C++ program for above implementation
#include
using namespace std;
// Make the largest even number
string makeEven(string str)
{
int n = str.length();
int even = INT_MAX, index;
// Start traversing the string
for (int i = 0; i < n - 1; i++) {
// Find the even number
if ((str[i] - '0') % 2 == 0) {
even = (str[i] - '0');
index = i;
}
// Check if current even is equal to
// or less than the odd number
if (even <= (str[n - 1] - '0'))
break;
}
// Return original string if there is no
// even value
if (even == INT_MAX)
return str;
// Swap even and odd value
swap(str[index], str[n - 1]);
return str;
}
// Driver code
int main()
{
string str = "1356425";
cout << makeEven(str);
return 0;
}
Java
// Java program for above implementation
class GFG {
// Make the largest even number
static char[] makeEven(String string) {
char []str = string.toCharArray();
int n = str.length;
int even = Integer.MAX_VALUE, index = 0;
// Start traversing the String
for (int i = 0; i < n - 1; i++) {
// Find the even number
if ((str[i] - '0') % 2 == 0) {
even = (str[i] - '0');
index = i;
}
// Check if current even is equal to
// or less than the odd number
if (even <= (str[n-1] - '0')) {
break;
}
}
// Return original String if there is no
// even value
if (even == Integer.MAX_VALUE) {
return str;
}
// Swap even and odd value
swap(str,index, n - 1);
return str;
}
static void swap(char[] str,int index1,int index2){
char temp = str[index1];
str[index1] = str[index2];
str[index2] =temp;
}
// Driver code
public static void main(String[] args) {
String str = "1356425";
System.out.print(makeEven(str));
}
}
/*This code is contributed by PrinciRaj1992*/
Python3
# Python3 code for the above implementation
import sys
# Make the largest even number
def makeEven(arr, n):
# index to first even no,if any
first_e_i = -1
# index to last even no, if any
last_e_i = -1
# index to last no
last_n_i = n - 1
# Start traversing the String
for i in range(n):
# if it finds any first even no less
# than last digit then break the loop
if (int(arr[i]) % 2 == 0 and
int(arr[i]) < int(arr[last_n_i])):
first_e_i = i
break
# it finds last even no
if int(arr[i]) % 2 == 0:
last_e_i = i
if first_e_i != -1:
# swap even and odd value
(arr[first_e_i],
arr[last_n_i]) = (arr[last_n_i],
arr[first_e_i])
return arr
if first_e_i == -1 and last_e_i != -1:
# swap even and odd value
(arr[last_e_i],
arr[last_n_i]) = (arr[last_n_i],
arr[last_e_i])
return arr
# Return original String if there is
# no even number
return arr
# Driver Code
if __name__=='__main__':
string="1356425"
result = "".join(makeEven(list(string),
len(list(string))))
print(result)
# This code is contributed
# by Vikash Kumar 37
C#
// C# implementation of above approach
using System;
public class GFG {
// Make the largest even number
static char[] makeEven(String str1) {
char []str = str1.ToCharArray();
int n = str.Length;
int even = int.MaxValue, index = 0;
// Start traversing the String
for (int i = 0; i < n - 1; i++) {
// Find the even number
if ((str[i] - '0') % 2 == 0) {
even = (str[i] - '0');
index = i;
}
// Check if current even is equal to
// or less than the odd number
if (even <= (str[n-1] - '0')) {
break;
}
}
// Return original String if there is no
// even value
if (even == int.MaxValue) {
return str;
}
// Swap even and odd value
swap(str,index, n - 1);
return str;
}
static void swap(char[] str,int index1,int index2){
char temp = str[index1];
str[index1] = str[index2];
str[index2] =temp;
}
// Driver code
public static void Main() {
String str = "1356425";
Console.WriteLine(makeEven(str));
}
}
/*This code is contributed by PrinciRaj1992*/
PHP
Javascript
输出 :
1356524