示例:实现二进制搜索算法的Java程序
import java.util.Scanner;
// Binary Search in Java
class Main {
int binarySearch(int array[], int element, int low, int high) {
// Repeat until the pointers low and high meet each other
while (low <= high) {
// get index of mid element
int mid = low + (high - low) / 2;
// if element to be searched is the mid element
if (array[mid] == element)
return mid;
// if element is less than mid element
// search only the left side of mid
if (array[mid] < element)
low = mid + 1;
// if element is greater than mid element
// search only the right side of mid
else
high = mid - 1;
}
return -1;
}
public static void main(String args[]) {
// create an object of Main class
Main obj = new Main();
// create a sorted array
int[] array = { 3, 4, 5, 6, 7, 8, 9 };
int n = array.length;
// get input from user for element to be searched
Scanner input = new Scanner(System.in);
System.out.println("Enter element to be searched:");
// element to be searched
int element = input.nextInt();
input.close();
// call the binary search method
// pass arguments: array, element, index of first and last element
int result = obj.binarySearch(array, element, 0, n - 1);
if (result == -1)
System.out.println("Not found");
else
System.out.println("Element found at index " + result);
}
}
输出1
Enter element to be searched:
6
Element found at index 3
在这里,我们已使用Java扫描器类从用户那里获取输入。根据用户的输入,我们使用了二进制搜索来检查数组中是否存在该元素。
我们还可以使用递归调用来执行相同的任务。
int binarySearch(int array[], int element, int low, int high) {
if (high >= low) {
int mid = low + (high - low) / 2;
// check if mid element is searched element
if (array[mid] == element)
return mid;
// Search the left half of mid
if (array[mid] > element)
return binarySearch(array, element, low, mid - 1);
// Search the right half of mid
return binarySearch(array, element, mid + 1, high);
}
return -1;
}
在这里,方法binarySearch()
一直在调用自身,直到找到该元素或if
条件失败。
如果您想了解有关二进制搜索算法的更多信息,请访问二进制搜索算法。