以反螺旋形式打印矩阵的Python程序

给定一个二维数组，任务是以反螺旋形式打印矩阵：
例子：

输出：16 15 14 13 12 11 10 9 8 7 6 5 4 3 2 1

Input : arr[][4] = {1, 2, 3, 4
                    5, 6, 7, 8
                    9, 10, 11, 12
                    13, 14, 15, 16};
Output : 10 11 7 6 5 9 13 14 15 16 12 8 4 3 2 1

Input :arr[][6] = {1, 2, 3, 4, 5, 6
                  7, 8, 9, 10, 11, 12
                  13, 14, 15, 16, 17, 18};
Output : 11 10 9 8 7 13 14 15 16 17 18 12 6 5 4 3 2 1

这个想法很简单，我们以螺旋形式遍历矩阵并将所有遍历的元素放入堆栈中。最后从堆栈中逐一打印并打印它们。

Python 3

# Python 3 program to print
# matrix in anti-spiral form
R = 4
C = 5
  
def antiSpiralTraversal(m, n, a):
    k = 0
    l = 0
  
    # k - starting row index
    # m - ending row index
    # l - starting column index
    # n - ending column index
    # i - iterator 
    stk = []
  
    while (k <= m and l <= n):
          
        # Print the first row 
        # from the remaining rows 
        for i in range(l, n + 1):
            stk.append(a[k][i])
        k += 1
  
        # Print the last column 
        # from the remaining columns 
        for i in range(k, m + 1):
            stk.append(a[i][n])
        n -= 1
  
        # Print the last row
        # from the remaining rows 
        if ( k <= m):
            for i in range(n, l - 1, -1):
                stk.append(a[m][i])
            m -= 1
  
        # Print the first column 
        # from the remaining columns 
        if (l <= n):
            for i in range(m, k - 1, -1):
                stk.append(a[i][l])
            l += 1
          
    while len(stk) != 0:
        print(str(stk[-1]), end = " ")
        stk.pop()
  
# Driver Code
mat = [[1, 2, 3, 4, 5],
       [6, 7, 8, 9, 10],
       [11, 12, 13, 14, 15],
       [16, 17, 18, 19, 20]];
  
antiSpiralTraversal(R - 1, C - 1, mat)
  
# This code is contributed
# by ChitraNayal

输出：

12 13 14 9 8 7 6 11 16 17 18 19 20 15 10 5 4 3 2 1 

有关详细信息，请参阅以反螺旋形式打印矩阵的完整文章！