求加法逆:−7/9
任何可以使整个结果为零的数字都是加法逆。换句话说,当一个数乘以其加法逆元时,结果为零。如果我们将数字 1 乘以 -1,则结果为零。结果,1 的加法逆元为 -1。
即使在现实生活中,如果发现了精确的倒数,我们所感知的一切都可以归零。例如,正确数量的火和冰将相互抵消,结果将为零。
The value of an additive inverse of a number is defined as the value that when added to the original number yields zero. It’s the amount we add to a number to make it equal zero.
如果 x 是一个原始数,那么它的加法逆元是负 x 或 -x,如下所示:
x + (-x) = x – x = 0
因此,x 的加法逆是-x。
现在,在 -x 的情况下,即 -x 的加法逆必须是 x 或正数,如下所示:
(-x) + x = -x + x = 0
加法逆示例
- 3 的加法倒数是 -3。 (因为,3 + (-3) = 0)
- 40 的加法倒数是 -40。 (因为,40 + (-40) = 0)
- 100 的加法倒数是 100,(因为,100 + (-100) = 0)
- -2431 的加法逆元是 2431。(因为,(-2431) + 2431 = 0)
类似地,在分数的情况下,加法逆被给出为:
如果 (p/q) 是原始分数,则其加法逆元为负 (p/q) 或 (-p/q),如下所示:
p/q + (-p/q) = p/q – p/q = 0
因此,p/q 的加法逆是 -p/q。
现在,在 (-p/q) 的情况下,即 (-p/q) 的加法逆必须为 (p/q) 或正数,如下所示:
(-p/q) + p/q = -p/q + p/q = 0
求加法逆:−7/9
解决方案:
The given fraction is -7/9.
As we know that, the additive inverse of any fraction is given as:
p/q + (-p/q) = p/q – p/q = 0
This implies, the additive inverse of p/q is -p/q.
Now, in case of (-p/q) i.e. the additive inverse of (-p/q) must be (p/q) or positive as follows:
(-p/q) + p/q = -p/q + p/q = 0
Similarly, the additive inverse of -7/9 is 7/9 as follows:
(-7/9) + 7/9 = 0
Hence, the additive inverse of -7/9 is 7/9 or positive 7/9.
类似问题
问题 1:什么是 xy 的加法逆?
回答:
The additive inverse of xy is -xy as follows:
xy + (-xy) = xy – xy = 0
问题2:加法逆和加法恒等式之间是否有相似之处?
回答:
No, they’re not the same. The additive inverse occurs when you add two numbers together to achieve a zero result. The value that is added to get the original integer, which is zero, is called additive identity.
问题 3:什么是 1/100 的加法倒数?
回答:
The additive inverse of 1/100 is -1/100 as follows:
1/100 + (-1/100) = 1/100 – 1/100 = 0