对于1人游戏(用户与CPU)，请参阅井字游戏的实现
游戏规则
- 该游戏将在两个人之间进行(在此程序中，人与人之间)。
- 首先，游戏将以两个玩家的名字作为输入。
- 一个玩家选择“ O”，另一个选择“ X”以标记各自的单元格。
- 将有一场比赛折腾，这将决定哪个玩家先行动。
- 游戏从一名玩家开始，当一名玩家的整行/整列/对角线填充有他/她各自的字符(“ O”或“ X”)时，游戏结束。
- 如果游戏是平局，则显示一条消息“游戏为平局”。
_0.jpg)
取胜策略–有趣的事实
如果两个球员都发挥出最佳状态，那么注定您将永远不会输(“尽管仍然可以进行比赛”)。比赛第一还是第二都没关系。用另一种方式–“两个专家玩家将始终平局”。
这不是很有趣吗?
以下是该游戏的代码：
C++
// C++ program to play Tic-Tac-Toe
#include
using namespace std;
// Length of the board
#define SIDE 3
// Name fo the players
string PLAYER1, PLAYER2;
// Function to show the current
// board status
void showBoard(char board[][SIDE])
{
printf("\n\n");
printf("\t\t\t %c | %c | %c \n",
board[0][0],
board[0][1],
board[0][2]);
printf("\t\t\t------------\n");
printf("\t\t\t %c | %c | %c \n",
board[1][0],
board[1][1],
board[1][2]);
printf("\t\t\t------------\n");
printf("\t\t\t %c | %c | %c \n\n",
board[2][0],
board[2][1],
board[2][2]);
return;
}
// Function to show the instructions
void showInstructions()
{
printf("\t\t\t Tic-Tac-Toe\n\n");
printf("Choose a cell numbered "
"from 1 to 9 as below"
" and play\n\n");
printf("\t\t\t 1 | 2 | 3 \n");
printf("\t\t\t------------\n");
printf("\t\t\t 4 | 5 | 6 \n");
printf("\t\t\t------------\n");
printf("\t\t\t 7 | 8 | 9 \n\n");
printf("-\t-\t-\t-\t-\t"
"-\t-\t-\t-\t-\n\n");
return;
}
// Function to initialise the game
void initialise(char board[][SIDE],
int moves[])
{
// Initiate the random number
// generator so that the same
// configuration doesn't arises
srand(time(NULL));
// Initially the board is empty
for (int i = 0; i < SIDE; i++) {
for (int j = 0; j < SIDE; j++)
board[i][j] = ' ';
}
// Fill the moves with numbers
for (int i = 0; i < SIDE * SIDE; i++)
moves[i] = i;
// randomise the moves
random_shuffle(moves,
moves + SIDE * SIDE);
return;
}
// Function to declare winner of the game
void declareWinner(string whoseTurn)
{
if (whoseTurn == PLAYER1)
cout << PLAYER1 << " has won\n";
else
cout << PLAYER1 << " has won\n";
return;
}
// Function that returns true if
// any of the row is crossed with
// the same player's move
bool rowCrossed(char board[][SIDE])
{
for (int i = 0; i < SIDE; i++) {
if (board[i][0] == board[i][1]
&& board[i][1] == board[i][2]
&& board[i][0] != ' ')
return (true);
}
return (false);
}
// Function that returns true if any
// of the column is crossed with the
// same player's move
bool columnCrossed(char board[][SIDE])
{
for (int i = 0; i < SIDE; i++) {
if (board[0][i] == board[1][i]
&& board[1][i] == board[2][i]
&& board[0][i] != ' ')
return (true);
}
return (false);
}
// Function that returns true if any
// of the diagonal is crossed with
// the same player's move
bool diagonalCrossed(char board[][SIDE])
{
if (board[0][0] == board[1][1]
&& board[1][1] == board[2][2]
&& board[0][0] != ' ')
return (true);
if (board[0][2] == board[1][1]
&& board[1][1] == board[2][0]
&& board[0][2] != ' ')
return (true);
return (false);
}
// Function that returns true if the
// game is over else it returns a false
bool gameOver(char board[][SIDE])
{
return (rowCrossed(board)
|| columnCrossed(board)
|| diagonalCrossed(board));
}
// Function to play Tic-Tac-Toe
void playTicTacToe(string whoseTurn)
{
// A 3*3 Tic-Tac-Toe board for playing
char board[SIDE][SIDE];
int moves[SIDE * SIDE];
// Initialise the game
initialise(board, moves);
// Show instructions before playing
showInstructions();
int moveIndex = 0, x, y;
int r, c;
// Keep playing till the game is
// over or it is a draw
while (gameOver(board) == false
&& moveIndex != SIDE * SIDE) {
if (whoseTurn == PLAYER1) {
// Lable for player1 worng choice
// of row and column
player1:
// Input the desired row and
// column by player 1 to
// insert X
cout << PLAYER1
<< " Enter the respective"
<< " row and column to "
"insert X :\n";
cin >> r >> c;
if (r <= 3 && c <= 3) {
// To check desired row and
// column should be empty
if (board[r - 1] == ' ')
board[r - 1] = 'X';
// If input is on already
// filled position
else {
cout << "You cannot Overlap"
<< " on Already "
"filled position:\n";
goto player1;
}
}
// Input is not valid
else {
cout << "\nInput is not "
<< "valid please enter "
<< "right one\n";
goto player1;
}
showBoard(board);
moveIndex++;
whoseTurn = PLAYER2;
}
else if (whoseTurn == PLAYER2) {
// Lable for player2 worng choice
// of row and column
player2:
// Input the desired row and
// column by player 1 to
// insert X
cout << PLAYER2
<< " Enter the respective"
<< " row and column to "
"insert O :";
cin >> r >> c;
if (r <= 3 && c <= 3) {
// Input the desired row and
// column by player 1 to
// insert X
if (board[r - 1] == ' ')
board[r - 1] = 'O';
// If input is on already
// filled position
else {
cout << "You cannot Overlap"
<< " on Already "
<< "filled position:\n";
goto player2;
}
}
// Input is not valid
else {
cout << "\nInput is not "
<< "valid please enter "
<< "right one :\n";
goto player2;
}
showBoard(board);
moveIndex++;
whoseTurn = PLAYER1;
}
}
// If the game has drawn
if (gameOver(board) == false
&& moveIndex == SIDE * SIDE)
printf("It's a draw\n");
else {
// Toggling the user to declare
// the actual winner
if (whoseTurn == PLAYER1)
whoseTurn = PLAYER2;
else if (whoseTurn == PLAYER2)
whoseTurn = PLAYER1;
// Declare the winner
declareWinner(whoseTurn);
}
return;
}
// Driver Code
int main()
{
// Take the name of players
cout << "Enter name of first Player: ";
cin >> PLAYER1;
cout << "Enter name of Second Player: ";
cin >> PLAYER2;
// Use current time as seed for
// random generator
srand(time(0));
// Lets do toss
int toss = rand() % 2;
// Let us play the game
if (toss == 1) {
cout << "Player "
<< PLAYER1
<< " win the toss"
<< endl;
playTicTacToe(PLAYER1);
}
else {
cout << "Player "
<< PLAYER2
<< " win the toss"
<< endl;
playTicTacToe(PLAYER2);
}
return (0);
} 输出：
以下是上述代码的输出： _1.jpg)