问题1:通过依次减去数字,找到以下数字的立方根:1、7、19、37、61、91、127、169、217、271、331、397,…
(i)64
(ii)512
(iii)1728年
解决方案:
(i) 64
Performing successive subtraction:
64 – 1 = 63
63 – 7 = 56
56 – 19 =37
37 – 37 = 0
Since subtraction is performed 4 times.
Therefore, the cube root of 64 is 4.
(ii) 512
Performing successive subtraction:
512 – 1 = 511
511 – 7 = 504
504 – 19 = 485
485 – 37 = 448
448 – 61 = 387
387 – 91 = 296
296 – 127 = 169
169 – 169 = 0
Since subtraction is performed 8 times.
Therefore, the cube root of 512 is 8.
(iii) 1728
Performing successive subtraction:
1728 – 1 = 1727
1727 – 7 = 1720
1720 – 19 = 1701
1701 – 37 = 1664
1664 – 91 = 1512
1512 – 127 = 1385
1385 – 169 = 1216
1216 – 217 = 999
999 – 271 = 728
728 – 331 = 397
397 – 397 = 0
Since subtraction is performed 12 times.
Therefore, the cube root of 1728 is 12.
问题2:使用逐次减法的方法检查以下数字是否为理想的立方体:
(i)130
(ii)345
(iii)792
(iv)1331年
解决方案:
(i) 130
Performing successive subtraction:
130 – 1 = 129
129 – 7 = 122
122 – 19 = 103
103 – 37 = 66
66 – 61 = 5
Since the next number to be subtracted is 91, which is greater than 5
Therefore,130 is not a perfect cube.
(ii) 345
Performing successive subtraction:
345 – 1 = 344
344 – 7 = 337
337 – 19 = 318
318 – 37 = 281
281 – 61 = 220
220 – 91 = 129
129 – 127 = 2
Since the next number to be subtracted is 169, which is greater than 2
Therefore, 345 is not a perfect cube
(iii) 792
Performing successive subtraction:
792 – 1 = 791
791 – 7 = 784
784 – 19 = 765
765 – 37 = 728
728 – 61 = 667
667 – 91 = 576
576 – 127 = 449
449 – 169 = 280
280 – 217 = 63
Since the next number to be subtracted is 271, which is greater than 63
Therefore, 792 is not a perfect cube
(iv) 1331
Performing successive subtraction:
1331 – 1 = 1330
1330 – 7 = 1323
1323 – 19 = 1304
1304 – 37 = 1267
1267 – 61 = 1206
1206 – 91 = 1115
1115 – 127 = 988
988 – 169 = 819
819 – 217 = 602
602 – 271 = 331
331 – 331 = 0
Since subtraction is performed 11 times,
Therefore, Cube root of 1331 is 11
Hence, 1331 is a perfect cube.
问题3:找出必须从问题2中不是理想立方体的数字中减去的最小数,以使它们成为理想立方体。对应的多维数据集根是什么?
解决方案:
在上一个问题中,有三个数字不是完美的立方体。
(i) 130
Performing successive subtraction:
130 – 1 = 129
129 – 7 = 122
122 – 19 = 103
103 – 37 = 66
66 – 61 = 5
The next number which is to be subtracted is 91, which is greater than 5
Since, 130 is not a perfect cube.
Therefore, to make it a perfect cube we have to subtract 5.
130 – 5 = 125
125 is a perfect cube of 5.
(ii) 345
Performing successive subtraction:
345 – 1 = 344
344 – 7 = 337
337 – 19 = 318
318 – 37 = 281
281 – 61 = 220
220 – 91 = 129
129 – 127 = 2
The next number which is to be subtracted is 169, which is greater than 2
Since, 345 is not a perfect cube.
Therefore, to make it a perfect cube we have to subtract 2.
345 – 2 = 343
343 is a perfect cube of 7.
(iii) 792
Performing successive subtraction:
792 – 1 = 791
791 – 7 = 784
784 – 19 = 765
765 – 37 = 728
728 – 61 = 667
667 – 91 = 576
576 – 127 = 449
449 – 169 = 280
280 – 217 = 63
The next number which is to be subtracted is 271, which is greater than 63
Since, 792 is not a perfect cube.
Therefore, to make it a perfect cube we have to subtract 63.
792 – 63 = 729
729 is a perfect cube of 9.
问题4:找到以下每个自然数的立方根:
(i)343(ii)2744(iii)4913(iv)1728(v)35937(vi)17576(vii)134217728(viii)48228544(ix)74088000(x)157464(xi)1157625(xii)33698267
解决方案:
(i) 343
By prime factorizing 343, we get
∛343 = ∛ (7 × 7 × 7) = 7
Therefore, the cube root of 343 is 7
(ii) 2744
By prime factorizing 2744, we get
∛2744 = ∛ (2 × 2 × 2 × 7 × 7 × 7)
∛2744 = ∛ (23 × 73) = 2 × 7 = 14
Therefore, the cube root of 2744 is 14
(iii) 4913
By prime factorizing 4913, we get
∛4913 = ∛ (17 × 17 × 17) = 17
Therefore, the cube root of 4913 is 17
(iv) 1728
By prime factorizing 1728, we get
∛1728 = ∛(2 × 2 × 2 × 2 × 2 × 2 × 3 × 3 × 3)
∛1728 = ∛ (23 × 23 × 33) = 2 × 2 × 3 = 12
Therefore, the cube root of 1728 is 12
(v) 35937
By prime factorizing 35937, we get
∛35937 = ∛ (3 × 3 × 3 × 11 × 11 × 11)
∛35937 = ∛ (33 × 113) = 3 × 11 = 33
Therefore, the cube root of 35937 is 33
(vi) 17576
By prime factorizing 17576, we get
∛17576 = ∛ (2 × 2 × 2 × 13 × 13 × 13)
∛17576 = ∛ (23 × 133) = 2 × 13 = 26
Therefore, the cube root of 17576 is 26
(vii) 134217728
By prime factorizing 134217728, we get
∛134217728 = ∛ (227) = 29 = 512
Therefore, the cube root of 134217728 is 512
(viii) 48228544
By prime factorizing 48228544, we get
∛48228544 = ∛ (2 × 2 × 2 × 2 × 2 × 2 × 7 × 7 × 7 × 13 × 13 × 13)
∛48228544 = ∛ (23 × 23 × 73 × 133) = 2 × 2 × 7 × 13 = 364
Therefore, the cube root of 48228544 is 364
(ix) 74088000
By prime factorizing 74088000, we get
∛74088000 = ∛ (2 × 2 × 2 × 2 × 2 × 2 × 3 × 3 × 3 × 5 × 5 × 5 × 7 × 7 × 7)
∛74088000 = ∛ (23 × 23 × 33 × 53 × 73) = 2 × 2 × 3 × 5 × 7 = 420
Therefore, the cube root of 74088000 is 420
(x) 157464
By prime factorizing 157464, we get
∛157464 = ∛ (2 × 2 × 2 × 3 × 3 × 3 × 3 × 3 × 3 × 3 × 3 × 3)
∛157464 = ∛ (23 × 33 × 33 × 33) = 2 × 3 × 3 × 3 = 54
Therefore, the cube root of 157464 is 54
(xi) 1157625
By prime factorizing 1157625, we get
∛1157625 = ∛ (3 × 3 × 3 × 5 × 5 × 5 × 7 × 7 × 7)
∛1157625 = ∛ (33 × 53 × 73) = 3 × 5 × 7 = 105
Therefore, the cube root of1157625 is 105
(xii) 33698267
By prime factorizing 33698267, we get
∛33698267 = ∛ (17 × 17 × 17 × 19 × 19 × 19)
∛33698267 = ∛ (173 × 193) = 17 × 19 = 323
Therefore, the cube root of 33698267 is 323
问题5:找出最小的数字,将其乘以3600将使乘积成为一个完美的立方体。此外,找到产品的立方根。
解决方案:
By prime factorizing 3600, we get
3600 = 2 × 2 × 2 × 2 × 3 × 3 × 5 × 5
By forming groups in triplet of equal factors we get, 3600 = (2 × 2 × 2) × (3 × 3) × (5 × 5) × 2
Since, 2, 3 and 5 cannot form a triplet of equal factors.
Therefore, 3600 must be multiplied with 60 (2 × 2 × 3 × 5) to get a perfect cube.
3600 × 60 = 216000
Cube root of 216000 is
∛216000 = ∛ (60 × 60 × 60)
∛216000 = ∛ (603) = 60
Therefore, the smallest number which when multiplied with 3600 makes a perfect cube is 60.
问题6:将210125乘以最小数,以使乘积是一个理想的立方体。此外,找出产品的立方根。
解决方案:
By prime factorizing 210125, we get
210125 = 5 × 5 × 5 × 41 × 41
By forming groups in triplet of equal factors we get, 210125 = (5 × 5 × 5) × (41 × 41)
Since, 41 cannot form a triplet of equal factors.
Therefore, 210125 must be multiplied with 41 to get a perfect cube.
210125 × 41 = 8615125
Now, finding the cube root of 8615125
By using the prime factorization method, we get
8615125 = 5 × 5 × 5 × 41 × 41 × 41
Therefore, Cube root of product = ∛8615125 = ∛ (5 × 41) = 205
问题7: 8192必须除以的最小数是多少,才能使商成为一个完美的立方?同样,找到这样获得的商的立方根。
解决方案:
By prime factorizing 8192, we get
8192 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 = 23 × 23 × 23 × 2
By forming groups in triplet of equal factors we get, 8192 = (2×2×2)×(2×2×2)×(2×2×2)×(2×2×2)×2
Since, 2 cannot form a triplet of equal factors.
Therefore, 8192 must be divided by 2 to get a perfect cube.
8192/2 = 4096
Now, finding the cube root of 4096
By using the prime factorization method, we get
4096 = 2×2×2×2×2×2×2×2×2×2×2×2 = 23×23×23×23
Therefore, Cube root of 4096 = ∛4096 = ∛ (23×23×23×23) = 2×2×2×2 = 16
问题8:三个数字的比例为1:2:3。他们的立方体的总和是98784。找到数字。
解决方案:
Given, ratio of number is 1:2:3
Therefore, Let the number be x, 2x and 3x
According to the question, sum of their cube is 98784
x3 + (2x)3+ (3x)3 = 98784
x3 + 8x3 + 27x3 = 98784
36x3 = 98784
x3 = 98784/36
x = 2744
x = ∛2744 = ∛ (2 × 2 × 2 × 7 × 7 × 7)
x = 2×7
x = 14
So, the respected numbers are,
x = 14
2x = 2 × 14 = 28
3x = 3 × 14 = 42
问题9:立方体的体积为9261000 m 3 。找到立方体的一面。
解决方案:
Given, the volume of cube = 9261000 m3
Let the side of the cube be ‘x’ meter
Therefore, x3 = 9261000
Taking cube root on both the side,
x = ∛9261000 = ∛ (2×2×2×3×3×3×5×5×5×7×7×7) = ∛ (23×33×53×73) = 2×3×5×7 = 210
Hence, the side of cube is 210 meter