第二十一章测定II(长方体和立方体的体积和表面积)–练习21.1 |套装1
问题12:一个长方体的银块长9厘米,宽4厘米,高3.5厘米。用它制成每一个体积为1.5cm 3的珠子。查找可以从块中制成的珠子数量。
解决方案:
The details given about cuboidal block of silver are –
Length of cuboidal block = 9 cm
Breadth of cuboidal block = 4 cm
Height of cuboidal block = 3.5 cm
Volume of a cuboid = l * b * h
= 9 * 4 * 3.5
= 126 cm3
Number of beads = Volume of cuboid / Volume of bead
= 126 / 1.5
= 84 beads
问题13:求出2厘米乘3厘米乘10厘米的长方体盒子的数量,这些盒子可以存放在尺寸为40厘米,36厘米和24厘米的纸箱中。
解决方案:
The details given about cuboidal boxes are –
Length of cuboidal boxes = 2 cm
Breadth of cuboidal boxes = 3 cm
Height of cuboidal boxes = 10 cm
Volume of a cuboid = l * b * h
= 2 * 3 * 10
= 60 cm3
The details given about cartoon are –
Length of cartoon = 40 cm
Breadth of cartoon = 36 cm
Height of cartoon = 24 cm
Volume of a cartoon = l * b * h
= 40 * 36 * 24
= 34560 cm3
Number of boxes that can be stored in a cartoon = Volume of cartoon / Volume of cuboid
= 34560 / 60
= 576 boxes
问题14:一个长方体的实心铁块尺寸为50 cm,45 cm和34 cm,可以从该块中获得多少个5 cm x 3 cm x 2 cm的长方体。假设切割不会造成浪费。
解决方案:
The details given about cuboidal block are –
Length of cuboidal block = 50 cm
Breadth of cuboidal block = 45 cm
Height of cuboidal block = 34 cm
Volume of a cuboid = l * b * h
= 50 * 45 * 34
= 76500 cm3
The details given about cuboid are –
Length of cuboid = 5 cm
Breadth of cuboid = 3 cm
Height of cuboid = 2 cm
Volume of a cuboid = l * b * h
= 5 * 3 * 2
= 30 cm3
Number of boxes that can be stored in a cartoon = Volume of cartoon / Volume of cuboid
= 76500 / 30
= 2550 cuboids
问题15:立方体A的边长是立方体B的边长的三倍。立方体A的体积与立方体B的体积之比是多少?
解决方案:
Let side of cube B = x
Now side of cube A = 3x
Volume of cube A = (side)3
= (3x)3
= 27x3
Volume of cube B = (side)3
= (x)3
= x3
Volume of cube A / Volume of cube B = 27x3 / x3
= 27 : 1
问题16:一块冰激凌砖的尺寸为20厘米乘10厘米乘7厘米。可以在内部尺寸为100厘米x 50厘米x 42厘米的深冰箱中存储多少这种砖块?
解决方案:
有关冰砖的详细信息是-
冰块的长度–奶油砖= 20厘米
冰宽–奶油砖= 10厘米
冰的高度–奶油砖= 7厘米
冰淇凌砖的体积= l * b * h
= 20 * 10 * 7
= 1400厘米3
有关冰箱的详细信息是–
冰箱长度= 100厘米
冰箱宽度= 50厘米
冰箱高度= 42厘米
冰箱的容积= l * b * h
= 10 * 50 * 42
= 21000厘米3
冰箱中可以存储的砖块数量=冰箱的体积/砖块的体积
= 21000/14000
= 150块砖
问题17:假设有两个立方体,分别具有2 cm和4 cm的边缘。找到多维数据集的体积V 1和V 2并进行比较。
解决方案:
Volume of cube = (side)3
V1 = (2)3
= 8 cm3
Volume of cube = (side)3
V2 = (4)3
= 64
V1 / V2 = 8 / 64
V1 / V2 = 1 / 8
V2 = 8V1
问题18:茶包的尺寸为10厘米* 6厘米* 4厘米。在尺寸为50 cm * 30 cm * 0. 2 m的纸板箱中可以放置多少个这样的茶包?
解决方案:
The details given about tea – packet are –
Length of tea – packet = 10 cm
Breadth of tea – packet = 6 cm
Height of tea – packet = 4 cm
Volume of a tea – packet = l * b * h
= 10 * 6 * 4
= 240 cm3
The details given about cardboard box are –
Length of cardboard box = 50 cm
Breadth of cardboard = 30 cm
Height of cardboard = 0.2 m = 20 cm (1 m = 100 cm)
Volume of a cardboard box = l * b * h
= 50 * 30 * 20
= 30000 cm3
Number of tea – packets that can be placed in cardboard box = Volume of cardboard box / Volume of tea packet
= 30000 / 240
= 125 tea packet
问题19:5厘米x 4厘米x 3厘米大小的金属块的重量为1千克。找到一块大小为15厘米乘8厘米乘3厘米的相同金属的重量。
解决方案:
The details given metal block are –
Length of block = 5 cm
Breadth of block = 4 cm
Height of block = 3 cm
Volume of block = l * b * h
= 5 * 4 * 3
= 60 cm3
The details given about new box are –
Length of new block = 15 cm
Breadth of new block = 8 cm
Height of new block = 3 cm
Volume of new block = l * b * h
= 15 * 8 * 3
= 360 cm3
Weight of 60 cm3 block = 1 kg
Weight of 360 cm3 block = 360 / 60
= 6 kg
问题20:如果一块soap蛋糕的尺寸为7厘米* 5厘米* 2.5厘米,可以在一个56厘米* 0.4 m * 0.25 m的盒子中放置多少块soap蛋糕?
解决方案:
The details given about box are –
Length of box = 56 cm
Breadth of box = 0.4 m = 40 cm (1 m = 100 cm)
Height of box = 0.25 m = 25 cm (1m = 100 cm)
Volume of a box = l * b * h
= 56 * 40 * 25
= 56000 cm3
The details given about soap cake are –
Length of soap cake = 7 cm
Breadth of soap cake = 5 cm
Height of soap cake = 2.5 cm
Volume of a soap cake = l * b * h
= 7 * 5 * 2.5
= 87.5 cm3
Number of soap cakes that can be placed in a box = Volume of cardboard box / Volume of soap cake
= 56000 / 87.5
= 640 soap cakes
问题21:一个长方体盒子的体积为48 cm 3 。如果其高度和长度分别为3 cm和4 cm,则找到其宽度。
解决方案:
The details given about cuboidal box are
Volume of a cuboidal box = 48 cm3
Height of a cuboidal box = 3 cm
Length of a cuboidal box = 4 cm
Let height of cuboidal box = h
Volume of cuboid = l * b * h
48 = 3 * 4 * h
48 = 12 * h
h = 4 cm