以下C程序的输出是什么?
void count(int n)
{
static int d = 1;
printf("%d ", n);
printf("%d ", d);
d++;
if(n > 1) count(n-1);
printf("%d ", d);
}
int main()
{
count(3);
}
(A) 3 1 2 2 1 3 4 4 4
(B) 3 1 2 1 1 1 2 2 2
(C) 3 1 2 2 1 3 4
(D) 3 1 2 1 1 1 2答案： (A)
解释：
count(3) will print value of n and d. So 3 1 will be printed
and d will become 2.
Then count(2) will be called. It will print value of n and d.
So 2 2 will be printed and d will become 3.
Then count(1) will be called. It will print value of n and d.
So 1 3 will be printed and d will become 4.
Now count(1) will print value of d which is 4. count(1) will
finish its execution.
Then count(2) will print value of d which is 4.
Similarly, count(3) will print value of d which is 4.
So series will be A.
这个问题的测验