📜  门| GATE-CS-2014-(Set-2) |问题 11

📅  最后修改于: 2021-09-24 06:15:13             🧑  作者: Mango

IT 办公室的安全系统由 10 台计算机组成,其中正好有 4 台在工作。为了检查系统是否正常工作,官员们检查了随机挑选的四台电脑(没有更换)。如果被检查的四台计算机中至少有三台正在工作,则该系统被视为正常工作。让系统被认为是有功能的概率用 p 表示。那么 100p = ____________。
(一) 11.85答案:(一)
解释:

Total ways to pick 4 computers = 10*9*8*7

Total ways that at least three computers are fine = 
        Total ways that all 4 are fine + Total ways any 3 are fine

Total ways that all 4 are fine = 4*3*2*1

Total ways three are fine = 1st is Not working and other 3 working + 
                            2nd is Not working and other 3 working + 
                            3rd is Not working and other 3 working + 
                            4th is Not working and other 3 working + 
                         = 6*4*3*2 + 4*6*3*2 + 4*3*6*2 + 4*3*2*6
                         = 6*4*3*2*4


The probability = Total ways that at least three computers are fine /  
                  Total ways to pick 4 computers 
                =  (4*3*2*1 + 6*4*3*2*4) / (10*9*8*7)
                = (4*3*2*25) / (10*9*8*7)
                = 11.9% 

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