求四边形内角的程序

鉴于四边形的所有角都在 AP 中具有公差“d”，任务是找到所有角。
例子：

Input: d = 10
Output: 75, 85, 95, 105

Input: d = 20
Output: 60, 80, 100, 120

方法：

We know that the angles of the quadrilateral are in AP and having the common difference ‘d’. 
So, if we assume the first angle to be ‘a’ then the other angles can be calculated as, 
‘a+d’, ‘a+2d’ and ‘a+3d’ 
And, from the properties of quadrilaterals, the sum of all the angles of a quadrilateral is 360. So, 
(a) + (a + d) + (a + 2*d) + (a + 3*d) = 360 
4*a + 6*d = 360 
a = (360 – (6*d)) / 4 
where ‘a’ is the angle assumed in the beginning and ‘d’ is the common difference. 
 

下面是上述方法的实现：

C++

// C++ implementation of the approach
#include 
#define ll long long int
using namespace std;
 
// Driver code
int main()
{
    int d = 10;
    double a;
 
    // according to formula derived above
    a = (double)(360 - (6 * d)) / 4;
 
    // print all the angles
    cout << a << ", " << a + d << ", " << a + (2 * d)
         << ", " << a + (3 * d) << endl;
    return 0;
}

Java

// java implementation of the approach
 
import java.io.*;
 
class GFG {
  
// Driver code
 
    public static void main (String[] args) {
            int d = 10;
    double a;
 
    // according to formula derived above
    a = (double)(360 - (6 * d)) / 4;
 
    // print all the angles
    System.out.print( a + ", " + (a + d) + ", " + (a + (2 * d))
        + ", " + (a + (3 * d)));
    }
}
//This code is contributed
//by  inder_verma

Python

# Python implementation
# of the approach
d = 10
a = 0.0
 
# according to formula
# derived above
a=(360 - (6 * d)) / 4
 
# print all the angles
print(a,",", a + d, ",", a + 2 * d,
        ",", a + 3 * d, sep = ' ')
 
# This code is contributed
# by sahilshelangia

C#

// C# implementation of the approach
using System;
 
class GFG
{
 
// Driver code
public static void Main ()
{
    int d = 10;
    double a;
     
    // according to formula derived above
    a = (double)(360 - (6 * d)) / 4;
     
    // print all the angles
    Console.WriteLine( a + ", " + (a + d) +
                           ", " + (a + (2 * d)) +
                           ", " + (a + (3 * d)));
}
}
 
// This code is contributed
// by anuj_67

Javascript

 
// Javascript implementation of the approach
 
// Driver code
var d = 10;
var a;
 
// according to formula derived above
a = parseInt((360 - (6 * d)) / 4);
 
// print all the angles
document.write( a + ", " + (a + d) + ", " + (a + (2 * d))
    + ", " + (a + (3 * d)));
 
 

输出：

75, 85, 95, 105