Python| sympy.multiplicity() 方法

在sympy.multiplicity()方法的帮助下，我们可以找到最大的整数m使得p的m次方除以n ，其中p和n是该方法的参数

Syntax:
multiplicity(p, n)

Parameter:
p – It denotes an integer.
n – It denotes an integer.

Returns:
Returns the greatest integer m such that p^m divides n.

示例 #1：

# import multiplicity() method from sympy
from sympy import multiplicity
  
p = 2
n = 64
  
# Use multiplicity() method 
multi_p_n = multiplicity(p, n) 
      
print("{} is the largest integer such that {}^{} divides {}.".
      format(multi_p_n, p, multi_p_n, n))

输出：

6 is the largest integer such that 2^6 divides 64.

示例 #2：

# import multiplicity() method from sympy
from sympy import multiplicity
  
p = 3
n = 111
  
# Use multiplicity() method 
multi_p_n = multiplicity(p, n) 
      
print("{} is the largest integer such that {}^{} divides {}.".
      format(multi_p_n, p, multi_p_n, n))

输出：

1 is the largest integer such that 3^1 divides 111.