第N次折叠后的正方形面积程序

正方形是在一个平面上的平面形状，由四个角的四个点定义。一个正方形具有四个等长的边和四个直角(90度角)的角。正方形是一种矩形。

给定一个边的平方$N$和倍数$F$ 。任务是在F折后找到正方形的面积。

正方形的折叠如下：

1. 在第1折中，将正方形从左到右折成一个三角形。
2. 在第二折中，从上至下折叠正方形。
3. 在第三折中，再次从左至右折叠正方形。

   等等。

例子：

Input : N = 4, F = 2
Output : 2
Explanation: 
Initially square side is 4 x 4
After 1st folding, square side becomes 4 x 2
After 2nd folding, square side becomes 2 x 2
Thus area equals 2 x 2 = 4.

Input : N = 100, F = 6
Output : 156.25

方法：

• 折叠之前首先计算正方形的面积。
• 每次折叠后，正方形的面积减小一半。也就是说， area = area / 2 。
• 因此，我们最终将平方面积除以pow(2，F)

下面是上述方法的实现：

C++

// CPP program to find
// the area of the square
#include 
using namespace std;
  
// Function to calculate area of square after 
// given number of folds
double areaSquare(double side, double fold)
{
    double area = side * side;
  
    return area * 1.0 / pow(2, fold);
}
  
// Driver Code
int main()
{
    double side = 4, fold = 2;
  
    cout << areaSquare(side, fold);
  
    return 0;
}

Java

// Java program to find the area of the square
class GFG
{
  
    // Function to calculate area of square
    // after given number of folds
    static double areaSquare(double side,
                            double fold)
    {
        double area = side * side;
      
        return area * 1.0 / Math.pow(2, fold);
    }
      
    // Driver Code
    public static void main(String []args)
    {
        double side = 4, fold = 2;
      
        System.out.println(areaSquare(side, fold));
    }
}
  
// This code is contributed
// by aishwarya.27

Python3

# Python3 program to find the area 
# of the square 
  
# Function to calculate area of 
# square after given number of folds 
def areaSquare(side, fold) :
        area = side * side
        ans = area / pow(2, fold)
        return ans
  
# Driver Code 
if __name__ == "__main__" :
          
    side = 4
    fold = 2
    print(areaSquare(side, fold))
  
# This code is contributed by Ryuga

C#

// C# program to find the area of the square
using System;
  
class GFG
{
      
// Function to calculate area of square
// after given number of folds
static double areaSquare(double side, 
                         double fold)
{
    double area = side * side;
  
    return area * 1.0 / Math.Pow(2, fold);
}
  
// Driver Code
public static void Main()
{
    double side = 4, fold = 2;
  
    Console.Write(areaSquare(side, fold));
}
}
  
// This code is contributed
// by Akanksha Rai

输出：

4