2的最高幂除以二进制表示的数字

给定二进制字符串str ，任务是找到2的最大幂，该幂除以给定二进制数的十进制等效值。

例子：

Input: str = “100100”
Output: 2
2² = 4 is the highest power of 2 that divides 36 (100100).

Input: str = “10010”
Output: 1

方法：从右边开始，在二进制表示形式中计算0的数量，这是将2除以该数字的最高幂。

下面是上述方法的实现：

C++

// C++ implementation of the approach
#include 
using namespace std;
  
// Function to return the highest power of 2
// which divides the given binary number
int highestPower(string str, int len)
{
  
    // To store the highest required power of 2
    int ans = 0;
  
    // Counting number of consecutive zeros
    // from the end in the given binary string
    for (int i = len - 1; i >= 0; i--) {
        if (str[i] == '0')
            ans++;
        else
            break;
    }
  
    return ans;
}
  
// Driver code
int main()
{
    string str = "100100";
    int len = str.length();
    cout << highestPower(str, len);
  
    return 0;
}

Java

// Java implementation of the approach
class GFG
{
      
// Function to return the highest power of 2
// which divides the given binary number
static int highestPower(String str, int len)
{
  
    // To store the highest required power of 2
    int ans = 0;
  
    // Counting number of consecutive zeros
    // from the end in the given binary string
    for (int i = len - 1; i >= 0; i--) 
    {
        if (str.charAt(i) == '0')
            ans++;
        else
            break;
    }
  
    return ans;
}
  
// Driver code
public static void main(String[] args)
{
    String str = "100100";
    int len = str.length();
    System.out.println(highestPower(str, len));
}
}
  
// This code is contributed by Code_Mech.

Python3

# Python3 implementation of the approach
  
# Function to return the highest power of 2
# which divides the given binary number
def highestPower(str, lenngth):
  
    # To store the highest required power of 2
    ans = 0;
  
    # Counting number of consecutive zeros
    # from the end in the given binary string
    for i in range(lenngth-1,-1,-1):
        if (str[i] == '0'):
            ans+=1;
        else:
            break;
    return ans;
  
# Driver code
def main():
    str = "100100";
    lenngth = len(str);
    print(highestPower(str, lenngth));
  
if __name__ == '__main__':
    main()
  
# This code contributed by PrinciRaj1992

C#

// C# implementation of the approach
using System;
      
class GFG
{
      
// Function to return the highest power of 2
// which divides the given binary number
static int highestPower(String str, int len)
{
  
    // To store the highest required power of 2
    int ans = 0;
  
    // Counting number of consecutive zeros
    // from the end in the given binary string
    for (int i = len - 1; i >= 0; i--) 
    {
        if (str[i] == '0')
            ans++;
        else
            break;
    }
  
    return ans;
}
  
// Driver code
public static void Main(String[] args)
{
    String str = "100100";
    int len = str.Length;
    Console.WriteLine(highestPower(str, len));
}
}
  
/* This code contributed by PrinciRaj1992 */

PHP

= 0; $i--)
    { 
        if ($str[$i] == '0') 
            $ans++; 
        else
            break; 
    } 
  
    return $ans; 
} 
  
// Driver code 
$str = "100100"; 
$len = strlen($str); 
echo highestPower($str, $len); 
  
// This code is contributed by Ryuga
?>

输出：

2