给定半径的给定两个圆,它们的中心之间相距给定的距离,这样,圆就不会彼此接触。任务是找到圆之间的直接公切线的长度。
例子:
Input: r1 = 4, r2 = 6, d = 12
Output: 11.8322
Input: r1 = 5, r2 = 9, d = 25
Output: 24.6779
方法:
- 令圆的半径分别为r1和r2 。
- 设中心之间的距离为d单位。
- 画一条线或平行于PQ
- 角度OPQ = 90度
角度O’QP = 90度
{将圆心与接触点连接的线与切线成90度角} - 角度OPQ +角度O’QP = 180度
OP ||二维码 - 由于相对的边平行并且内角为90,因此OPQR为矩形。
- 因此OP = QR = r1且PQ = OR = d
- 在三角形OO’R
角ORO’= 90
毕达哥拉斯定理
OR ^ 2 + O’R ^ 2 =(OO’^ 2)
OR ^ 2 +(r1-r2)^ 2 = d ^ 2 - 因此, OR ^ 2 = d ^ 2-(r1-r2)^ 2
OR =√{d ^ 2-(r1-r2)^ 2}
下面是上述方法的实现:
C++
// C++ program to find
// the length of the direct
// common tangent between two circles
// which donot touch each other
#include
using namespace std;
// Function to find the length of the direct common tangent
void lengtang(double r1, double r2, double d)
{
cout << "The length of the direct"
<<" common tangent is "
<< sqrt(pow(d, 2) - pow((r1 - r2), 2))
<< endl;
}
// Driver code
int main()
{
double r1 = 4, r2 = 6, d = 12;
lengtang(r1, r2, d);
return 0;
}
Java
// Java program to find
// the length of the direct
// common tangent between two circles
// which donot touch each other
class GFG
{
// Function to find the length of
// the direct common tangent
static void lengtang(double r1, double r2, double d)
{
System.out.println("The length of the direct"
+" common tangent is "
+(Math.sqrt(Math.pow(d, 2) -
Math.pow((r1 - r2), 2))));
}
// Driver code
public static void main(String[] args)
{
double r1 = 4, r2 = 6, d = 12;
lengtang(r1, r2, d);
}
}
/* This code contributed by PrinciRaj1992 */
Python3
# Python3 program to find
# the length of the direct
# common tangent between two circles
# which do not touch each other
import math
# Function to find the length
# of the direct common tangent
def lengtang(r1, r2, d):
print("The length of the direct common tangent is",
(((d ** 2) - ((r1 - r2) ** 2)) ** (1 / 2)));
# Driver code
r1 = 4; r2 = 6; d = 12;
lengtang(r1, r2, d);
# This code is contributed by 29AjayKumar
C#
// C# program to find
// the length of the direct
// common tangent between two circles
// which donot touch each other
using System;
class GFG
{
// Function to find the length of
// the direct common tangent
static void lengtang(double r1, double r2, double d)
{
Console.WriteLine("The length of the direct"
+" common tangent is "
+(Math.Sqrt(Math.Pow(d, 2) -
Math.Pow((r1 - r2), 2))));
}
// Driver code
public static void Main()
{
double r1 = 4, r2 = 6, d = 12;
lengtang(r1, r2, d);
}
}
// This code is contributed by AnkitRai01
PHP
Javascript
输出:
The length of the direct common tangent is 11.8322