给定一个边长为a的立方体。任务是找到可以在其中刻出的最大右圆柱的体积。
例子:
Input : a = 4
Output : 50.24
Input : a = 5
Output : 98.125
方法:
让:
- 圆柱体的高度为h 。
- 圆柱半径为r 。
从图中可以清楚地看出:
- 圆柱体的高度=立方体的侧面
- 圆柱体的半径=立方体的侧面/ 2
所以,
h = a
r = a/2
下面是上述方法的实现:
C++
// C++ Program to find the biggest right
// circular cylinder that can be fit within a cube
#include
using namespace std;
// Function to find the biggest right circular cylinder
float findVolume(float a)
{
// side cannot be negative
if (a < 0)
return -1;
// radius of right circular cylinder
float r = a / 2;
// height of right circular cylinder
float h = a;
// volume of right circular cylinder
float V = 3.14 * pow(r, 2) * h;
return V;
}
// Driver code
int main()
{
float a = 5;
cout << findVolume(a) << endl;
return 0;
}
Java
// Java Program to find the biggest right
// circular cylinder that can be fit within a cube
import java.io.*;
class GFG {
// Function to find the biggest right circular cylinder
static float findVolume(float a)
{
// side cannot be negative
if (a < 0)
return -1;
// radius of right circular cylinder
float r = a / 2;
// height of right circular cylinder
float h = a;
// volume of right circular cylinder
float V = (float)(3.14 * Math.pow(r, 2) * h);
return V;
}
// Driver code
public static void main (String[] args) {
float a = 5;
System.out.print(findVolume(a));
}
}
// This code is contributed by anuj_67..
Python3
# Python3 Program to find the biggest
# right circular cylinder that can be
# fit within a cube
# Function to find the biggest right
# circular cylinder
def findVolume(a) :
# side cannot be negative
if (a < 0) :
return -1
# radius of right circular cylinder
r = a / 2
# height of right circular cylinder
h = a
# volume of right circular cylinder
V = 3.14 * pow(r, 2) * h
return V
# Driver code
if __name__ == "__main__" :
a = 5
print(findVolume(a))
# This code is contributed by Ryuga
C#
// C# Program to find the biggest right
// circular cylinder that can be fit within a cube
using System;
class GFG {
// Function to find the biggest right circular cylinder
static float findVolume(float a)
{
// side cannot be negative
if (a < 0)
return -1;
// radius of right circular cylinder
float r = a / 2;
// height of right circular cylinder
float h = a;
// volume of right circular cylinder
float V = (float)(3.14 * Math.Pow(r, 2) * h);
return V;
}
// Driver code
public static void Main () {
float a = 5;
Console.WriteLine(findVolume(a));
}
}
// This code is contributed by anuj_67..
PHP
Javascript
输出:
98.125