Jane 拥有的卡片数量是 peter 的 3 倍，两个孩子平均拥有的卡片数量为 64 张。 Jane 拥有多少张卡片？

引入了一个系统来定义从负无穷到正无穷的数字。该系统被称为数字系统。数系很容易在数轴上表示，整数、整数、自然数都可以在数轴上定义。数轴包含正数、负数和零。

方程是一种数学语句，它用“=”符号连接两个相等值的代数表达式。例如：在等式 3x+2 = 5 中，3x+ 2 是左侧表达式，5 是与“=”符号连接的右侧表达式。

主要有3种方程：

• 线性方程
• 二次方程
• 多项式方程

在这里，我们将研究线性方程组。

一个变量的线性方程是写成 ax + b = 0 的方程，其中 a 和 b 是两个整数，x 是一个变量，并且只有一个解。例如，3x + 2 = 5 是一个只有一个变量的线性方程。因此，这个方程只有一个解，即 x = 3/11。另一方面，两个变量的线性方程有两个解。

A one-variable linear equation is one with a maximum of one variable of order one. The formula is ax + b = 0, using x as the variable.

这个方程只有一个解。这里有一些例子：

• 4x = 8
• 5x + 10 = -20
• 1 + 6x = 11

一个变量中的线性方程以标准形式写成：

ax + b = 0

Here,

• The numbers ‘a’ and ‘b’ are real.
• Neither ‘a’ nor ‘b’ are equal to zero.

求解一个变量中的线性方程

求解只有一个变量的方程的步骤如下：

步骤 1：如果有任何分数，请使用 LCM 将其删除。

第 2 步：等式两边都应该简化。

第 3 步：从方程中删除变量。

第 4 步：确保您的回答是正确的。

Average of numbers: Average of  ‘N’ numbers is the total value/sum of N numbers divided by N i.e. 
Average of two numbers = (num1 + num2)/2
Average of three numbers = (num1 + num2 + num3)/2
and so on….

For example of Average of 4 and 6 will be (4 + 6)/2 = 10/2 i.e. 5

示例：两个学生的分数分别为 70 和 80。找出平均分。

解决方案：

Average of two numbers are the sum of both numbers divided by 2.
So, here the average marks will be (70 + 80)/2 i..e 150/2 = 75. 

Jane 的卡片数量是 peter 的 3 倍，两个孩子平均拥有的卡片数量为 64。Jane 有多少张卡片？

解决方案：

Let Peter have ‘x’  and Jane have ‘y’ number of cards respectively.

So, According to given statement
No. of cards Jane have = 3 * (No. of cards peter have )
i.e. y = 3x (Equation 1)

Also, it is given that average of both cards = 64 i.e.

(x + y)/2 = 64
Put the value of y = 3x from equation 1
(x + 3x) / 2 = 64
(4x) / 2 = 64
2x = 64
x = 64 / 2 
x = 32

So, y = 3x i.e. 
y = 3 * 32 = 96
So, the number of cards Peter and Jane have are 32 and 96 respectively.

类似问题

问题 1：A 拥有 B 的 2 倍硬币，双方平均拥有 21 枚硬币。A 拥有多少枚硬币？

解决方案：

Let A have ‘y’  and B have ‘x’ number of coins respectively.

So, According to given statement
No. of coins A have = 2 * (No. of coins B have)
i.e. y = 2x (Equation 1)

Also, it is given that average of both coins = 21 i.e.

(x + y) / 2 = 21
Put the value of y = 2x from equation 1
(x + 2x) / 2 = 21
(3x) / 2 = 21
3x = 42
x = 42 / 3
x = 14

So, y = 2x i.e. y = 2 * 14 = 28
So, the number of coins A and B have are 28 and 14 respectively.

问题 2：A 的苹果数量是 B 的 5 倍，两人拥有的苹果总数为 48，请问两人各有多少个苹果？

解决方案：

Let A have ‘y’  and B have ‘x’ number of cards respectively.

So, According to given statement
No. of apples A have = 5 * (No. of apples B have )
i.e. y = 5x (Equation 1)

Also, it is given that total apples = 48 i.e.

(x + y)  = 48
Put the value of y = 5x from equation 1
(x + 5x) = 48
6x = 48
6x = 48
x = 48 / 6
x = 8

So, y = 5x i.e. y = 5 * 8 = 40
So, the number of apples A and B have are 40 and 8 respectively.