以之字形形式打印给定的矩阵

给定一个二维数组，以之字形打印它。
例子 ：

Input : 
        1    2   3   4   5
        6    7   8   9   10
        11   12  13  14  15
        16  17  18  19   20
Output :
1 2 3 4 5 10 9 8 7 6 11 12 13 14 15 20 19 18 17 16 


Input :
        10    24   32   
        50    6    17   
        99    10   11  
         
Output :
10 24 32 17 6 50 99 10 11

C++

// C++ program to print
// matrix in zig-zag form
#include 
using namespace std;
  
    // Method to print matrix in zig-zag form
    void printZigZag(int row, int col, int a[][5])
    {
        int evenRow = 0; //starts from the first row
        int oddRow = 1; //starts from the next row
  
        while (evenRow=0; i--)
                {
                // oddRow will be printed in
                    // the opposite direction
                cout<= 0; i--)
            {
                // oddRow will be printed in the opposite direction
                System.out.print(a[oddRow][i] + " "); 
            }
            }
          
            // Skipping next row so as to get the next oddRow
            oddRow = oddRow + 2; 
        } 
    }
  
    public static void main(String[] args)
    {
  
        int r = 3, c = 5;
  
        int mat[][] = { {1, 2, 3, 4, 5},
                         {6, 7, 8, 9, 10},
                         {11, 12, 13, 14, 15}};
  
        printZigZag(r , c , mat);
    }
}
# Python 3 program to print
# matrix in zig-zag form
  
# Method to print matrix 
# in zig-zag form
def printZigZag(row, col, a):
    evenRow = 0 # starts from the first row
    oddRow = 1 # starts from the next row
  
    while evenRow < row: 
        for i in range(col):
              
            # evenRow will be printed
            # in the same direction
            print(str(a[evenRow][i] ), 
                           end = " ")
                             
        # Skipping next row so as
        # to get the next evenRow
        evenRow = evenRow + 2
              
        if oddRow < row:
            for i in range(col - 1, -1, -1):
                  
                # oddRow will be printed in
                # the opposite direction
                print(str(a[oddRow][i]), 
                             end = " ")
                  
        # Skipping next row so as 
        # to get the next oddRow
        oddRow = oddRow + 2
  
# Driver Code 
r = 3
c = 5
  
mat = [[1, 2, 3, 4, 5],
       [6, 7, 8, 9, 10],
       [11, 12, 13, 14, 15]];
  
printZigZag(r , c , mat)
  
# This code is contributed 
# by ChitraNayal
// C# program to print matrix in zig-zag form
using System;
  
public class GFG {
      
    // Method to print matrix in zig-zag form
    static void printZigZag(int row, int col, int[, ] a)
    {
          
        // starts from the first row
        int evenRow = 0; 
          
        // starts from the next row
        int oddRow = 1; 
  
        while (evenRow < row) {
            for (int i = 0; i < col; i++) {
                  
                // evenRow will be printed in 
                // the same direction
                Console.Write(a[evenRow, i] + " ");
            }
  
            // Skipping next row so as to get the 
            // next evenRow
            evenRow = evenRow + 2;
  
            if(oddRow < row)
            {
                for (int i = col - 1; i >= 0; i--) 
                {
                  
                    // oddRow will be printed in the 
                    // opposite direction
                    Console.Write(a[oddRow, i] + " ");
                }
            }
  
            // Skipping next row so as to get 
            // the next oddRow
            oddRow = oddRow + 2;
        }
    }
  
    public static void Main()
    {
  
        int r = 3, c = 5;
          
        int[, ] mat = { { 1, 2, 3, 4, 5 },
                        { 6, 7, 8, 9, 10 },
                        { 11, 12, 13, 14, 15 }
                      };
  
        printZigZag(r, c, mat);
    }
}
  
// This code is contributed by vt_m.
= 0; $i--)
                {
                // oddRow will be printed in
                // the opposite direction
                echo $a[$oddRow][$i], " "; 
                }
            }
          
            // Skipping next row so as 
            // to get the next oddRow
            $oddRow = $oddRow + 2; 
        } 
    }
  
// Driver Code
$r = 3; $c = 5;
$mat = array(array(1, 2, 3, 4, 5),
             array(6, 7, 8, 9, 10),
             array(11, 12, 13, 14, 15));
  
printZigZag($r , $c , $mat);
      
// This code is contributed by m_kit.
?>