连续翻转 100 次头的几率是多少？
概率是结果发生的可能性。事件的概率仅在 0 和 1 之间，并且也以百分比形式表示。事件 A 的概率通常写为 P(A)。
每当我们不确定事件的结果时，我们就会使用某些结果的概率——它们发生的可能性有多大。对这些概率的分析称为统计。为了理解概率，我们举一个抛硬币的例子：
有两种可能的结果——正面或反面。
硬币落在反面的概率是多少？您可能直观地知道可能性是一半/一半或 50%。
概率公式
概率的类型
- 如果 P(A) < P(B)，则事件 A 和 B 发生的可能性不相等。
- 如果 P(A) = P(B)，则事件 A 和 B 发生的可能性相同。
连续翻转 100 次头的几率是多少？
解决方案：
Probability of an event = (Number of ways it can occur) / (total number of outcomes),
P(B) = (Number of ways B can happen) / (Total number of outcomes),
Probability of getting a Head = 1/2.
Tossing a coin is an independent event, it is not dependent on how many times it’s been tossed.
Probability of getting 2 heads in a row = probability of getting head first time × probability of getting head second time.
Probability of getting 2 heads in a row = (1/2) × (1/2).
Similarly, the probability of getting 100 heads in a row = (1/2)100.
类似问题
问题 1. 连续翻转 100 次的几率是多少？
解决方案：
Probability of an event = (Number of ways it can occur) / (total number of outcomes),
P(B) = (Number of ways B can happen) / (Total number of outcomes),
Probability of getting a tails = 1/2.
Tossing a coin is an independent event, it is not dependent on how many times it’s been tossed.
Probability of getting 2 tails in a row = probability of getting tails first time×probability of getting tail second time.
Probability of getting 2 tails in a row = (1/2) × (1/2).
Similarly, the probability of getting 100 tails in a row = (1/2)100.
问题 2. 连续翻转 10 次尾巴的几率是多少？
解决方案：
Probability of an event = (Number of ways it can occur) / (total number of outcomes),
P(B) = (Number of ways B can happen) / (Total number of outcomes),
Probability of getting a tails = 1/2.
Tossing a coin is an independent event, it is not dependent on how many times it’s been tossed.
Probability of getting 2 tails in a row = probability of getting tail first time×probability of getting tail second time.
Probability of getting 2 tails in a row = (1/2) × (1/2).
Similarly, the probability of getting 10 tails in a row = (1/2)10.