连续翻转12次正面的几率是多少？

概率是某事发生的可能性。事件的概率只能在 0 和 1 之间，也可以用百分比表示。事件 A 的概率通常写为 P(A)。

每当我们不确定事件的结果时，我们就会谈论某些结果的概率——它们发生的可能性有多大。对这些概率的分析称为统计。为了理解概率，我们举一个抛硬币的例子：

有两种可能的结果——正面或反面。

硬币正面朝上的概率是多少？您可能直观地知道可能性是一半/一半或 50%。但是我们如何解决这个问题？

概率的类型

• 如果 P(A) < P(B)，LHS 小于 RHS，则事件 A 和 B 发生的可能性不同。
• 如果 P(A) = P(B)，LHS 等于 RHS，则事件 A 和 B 发生的可能性相同。

使用的公式

$Probability \space of\space an\space event = \frac{Number\space of\space ways\space it\space can\space occur}{Total\space number\space of\space outcomes}$

$P(B) = \frac{Number\space of\space ways\space B\space occurs}{Total\space number\space of\space outcomes}$

连续翻转12次正面的几率是多少？

解决方案：

Probability of an event = (number of favorable event) / (total number of event).

P(B) = (occurence of Event B) / (total number of event).

Probability of getting a Head = 1/2.

Tossing a coin is an independent event, it is not dependent on how many times it’s been tossed.

Probability of getting 2 heads in a row = probability of getting head first time×probability of getting head second time.

Probability of getting 2 heads in a row  = (1/2) × (1/2).

Similarly, the probability of getting 12 heads in a row = (1/2)¹².

类似问题

问题 1. 连续翻转 20 次尾巴的几率是多少？

解决方案：

Probability of an event = (number of favorable event) / (total number of event).

P(B) = ((occurence of Event B) / (total number of event). 

Probability of getting a tails = 1/2.

Tossing a coin is an independent event, it is not dependent on how many times it’s been tossed.

Probability of getting 2 tails in a row = probability of getting tails first time×probability of getting tail second time.

Probability of getting 2 tails in a row  = (1/2) × (1/2).

Similarly, the probability of getting 20 tails in a row = (1/2)²⁰.

问题 2. 连续翻转 12 次尾巴的几率是多少？

解决方案：

Probability of an event =  (number of favorable event) / (total number of event).

P(B) = ((occurence of Event B) / (total number of event).

Probability of getting a tails = 1/2.

Tossing a coin is an independent event, it is not dependent on how many times it’s been tossed.

Probability of getting 2 tails in a row = probability of getting tail first time×probability of getting tail second time.

Probability of getting 2 tails in a row  = (1/2)×(1/2).

Similarly, the probability of getting 12 tails in a row = (1/2)¹².