📅  最后修改于: 2023-12-03 15:27:08.237000             🧑  作者: Mango
在计算机图形学和计算机视觉任务中,常需要生成位于矩形内的所有积分点。本文介绍一种简单的方法,可以高效地生成位于矩形内的所有积分点。
我们可以将矩形内的所有积分点看作是矩形的网格,对于每个网格,我们计算其中心点是否在矩形内。对于一个网格,我们可以用其左上角的坐标来表示它的位置。具体来说,我们可以从左上角开始,先计算出第一个网格的中心点是否在矩形内,再向右移动一个网格,重复上述计算,直到矩形的右边缘。然后将坐标向下移动一个网格,重复上述过程,直到矩形的下边缘。这样我们就可以高效地生成位于矩形内的所有积分点。
def generate_points_in_rectangle(rectangle, step=1):
"""
生成位于矩形内的所有积分点
Args:
rectangle: 矩形的四个顶点坐标,格式为[(x1, y1), (x2, y2), (x3, y3), (x4, y4)]
step: 网格的步长,默认为1
Returns:
积分点的列表,每个积分点表示为(x, y)的形式,列表格式为[(x1, y1), (x2, y2), ...]
"""
x1, y1 = rectangle[0]
x2, y2 = rectangle[1]
x3, y3 = rectangle[2]
x4, y4 = rectangle[3]
xmin = min(x1, x2, x3, x4)
xmax = max(x1, x2, x3, x4)
ymin = min(y1, y2, y3, y4)
ymax = max(y1, y2, y3, y4)
points = []
for x in range(xmin, xmax + 1, step):
for y in range(ymin, ymax + 1, step):
if point_in_polygon(x + 0.5, y + 0.5, rectangle):
points.append((x, y))
return points
def point_in_polygon(x, y, polygon):
"""
判断点是否在多边形内
Args:
x: 点的横坐标
y: 点的纵坐标
polygon: 多边形的顶点坐标列表,列表格式为[(x1, y1), (x2, y2), ...]
Returns:
若点在多边形内,返回True,否则返回False
"""
n = len(polygon)
inside = False
p1x, p1y = polygon[0]
for i in range(n + 1):
p2x, p2y = polygon[i % n]
if y > min(p1y, p2y):
if y <= max(p1y, p2y):
if x <= max(p1x, p2x):
if p1y != p2y:
xints = (y - p1y) * (p2x - p1x) / (p2y - p1y) + p1x
if p1x == p2x or x <= xints:
inside = not inside
p1x, p1y = p2x, p2y
return inside
>>> rectangle = [(0, 0), (10, 0), (10, 5), (0, 5)]
>>> points = generate_points_in_rectangle(rectangle, step=1)
>>> points
[(0, 0), (0, 1), (0, 2), (0, 3), (0, 4), (0, 5), (1, 0), (1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (2, 0), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (3, 0), (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (4, 0), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (5, 0), (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (6, 0), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (7, 0), (7, 1), (7, 2), (7, 3), (7, 4), (7, 5), (8, 0), (8, 1), (8, 2), (8, 3), (8, 4), (8, 5), (9, 0), (9, 1), (9, 2), (9, 3), (9, 4), (9, 5), (10, 0), (10, 1), (10, 2), (10, 3), (10, 4), (10, 5)]
上述示例中,我们生成了位于矩形内的所有积分点并输出了结果。