两个数字的和是 17，它们的差是 7。找出数字

引入了一个系统来定义从负无穷到正无穷的数字。该系统被称为数字系统。数系很容易在数轴上表示，整数、整数、自然数都可以在数轴上定义。数轴包含正数、负数和零。

方程是一种数学语句，它用“=”符号连接两个相等值的代数表达式。例如： 在等式 4x+2 = 8 中，4x+ 2 是左侧表达式，8 是与“=”符号连接的右侧表达式。

主要有3种方程：

• 线性方程
• 二次方程
• 多项式方程

在这里，我们将研究线性方程组。

一个变量的线性方程是写成 ax + b = 0 的方程，其中 a 和 b 是两个整数，x 是一个变量，并且只有一个解。例如，3x+ 2 = 5 是一个只有一个变量的线性方程。因此，这个方程只有一个解，即 x = 1。另一方面，一个有两个变量的线性方程有两个解。

A one-variable linear equation is one with a maximum of one variable of order one. The formula is ax + b = 0, using x as the variable.

这个方程只有一个解。这里有一些例子：

• 4x = 8
• 5x + 10 = -20
• 1 + 6x = 11

一个变量中的线性方程以标准形式写成：

ax + b = 0

Here,

• The numbers ‘a’ and ‘b’ are real.
• Neither ‘a’ nor ‘b’ are equal to zero.

求解一个变量中的线性方程

求解只有一个变量的方程的步骤如下：

步骤 1：如果有任何分数，请使用 LCM 将其删除。

第 2 步：等式两边都应该简化。

第 3 步：从方程中删除变量。

第 4 步：确保您的回答是正确的。

两个数字的和是 17，它们的差是 7。找出这些数字。

解决方案：

Let both numbers be first and second.

According to the problem statement:

first + second = 17 (Consider this as 1st equation)
first – second = 7  (Consider this as 2nd equation)

Add both equations:

first + second + first – second = 17 + 7
2 * first = 24
first = 24 / 2
first = 12

So from this we get first = 12, put this value in any equation i.e.

first + second = 17 (Put the value of first in this equation)
12 + second = 17
second = 17 – 12
second = 5

So, the numbers are 12 and 5.

If we consider the case i.e. second – first = 7, then the solution will be same and the first number will become 5 and second number will become 12.

示例问题

问题1：两个数之和是20，两个数之差是10。任务是找出这些数。

解决方案：

Let both numbers be first and second.

According to the problem statement:
first + second = 20 (Consider this as 1st equation)
first – second = 10  (Consider this as 2nd equation)

Add both equations:

first + second + first – second = 20 + 10
2 * first = 30
first = 30 / 2
first = 15

So from this we get first = 15, put this value in any equation i.e.

first + second = 20 (Put the value of first in this equation)
15 + second = 20
second = 20 – 15
second = 5

So, the numbers are 15 and 5.

If we consider the case i.e. second – first = 10 then the solution will be same and the first number will become 5 and second number will become 15.

问题2：哪两个数之和为9，差为5？

解决方案：

Let both numbers be first and second.

According to the problem statement:
first + second = 9 (Consider this as 1st equation)
first – second = 5  (Consider this as 2nd equation)

Add both equations:

first + second + first – second = 9 + 5
2 * first = 14
first = 14 / 2
first = 7

So from this we get first = 7, put this value in any equation i.e.

first + second = 9 (Put the value of first in this equation)
7 + second = 9
second = 9 – 7
second = 2

So, the numbers are 7 and 2.

If we consider the case i.e. second – first = 5, then the solution will be same and the first number will become 2 and second number will become 7.