📜  门| GATE-CS-2014-(Set-3)|第65章

📅  最后修改于: 2021-06-29 23:25:24             🧑  作者: Mango

考虑以下处理器(ns代表纳秒)。假设流水线寄存器的延迟为零。

P1: Four-stage pipeline with stage 
    latencies 1 ns, 2 ns, 2 ns, 1 ns.
P2: Four-stage pipeline with stage 
    latencies 1 ns, 1.5 ns, 1.5 ns, 1.5 ns.
P3: Five-stage pipeline with stage 
    latencies 0.5 ns, 1 ns, 1 ns, 0.6 ns, 1 ns.
P4: Five-stage pipeline with stage 
    latencies 0.5 ns, 0.5 ns, 1 ns, 1 ns, 1.1 ns. 

哪个处理器的峰值时钟频率最高?

(A) P1
(B) P2
(C) P3
(D) P4答案: (C)
解释:

Peak clock frequency = 1 / Maximum latency

Maximum of latencies is minimum in P3

i.e. 

P1 : f= 1/2 = 0.5 GHz

P2: f=1/1.5 = 0.67 GHz

P4: f=1/1.1 GHz

P3 : f=1/1 GHz =1

Thus P3 is be the right answer

该解释由Abhishek Kumar提供。
这个问题的测验