以下命题陈述不等于 ((A → B) → C) → ((A → C) → B)
注意 –此问题是多选题 (MSQ)。
(A) (B → C)
(B) (B → C’)
(C) (B’ → C’)
(D) (B’ → C)答案： (A) (B) (D)
解释：让我们解决它，
((A → B) → C) → ((A → C) → B)
= ((A’ + B)’ + C)’ + ((A’ + C)’ + B ) {we know A → B = A’ + B}
= ((AB’) + C)’ + AC’ + B
= (AB’)’C’ + AC’ + B
= (A’ + B)C’ + AC’ + B
= A’C’ + BC’ + AC’ + B
= (A + A’)C’ + (1 + C’)B
= C’ + B {A + A’ = 1 and 1 + C’ = 1}
= (B’ → C’) 所以，选项(C)等于给定的表达式。这个问题的测验
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