给定一个整数A ,表示立方体的长度,任务是找到立方体的对角线和向它倾斜的边之间的最短距离,即下图中的KL 。
例子 :
Input: A = 2
Output: 1.4142
Explanation:
Length of KL = A / √2
Length of KL = 2 / 1.41 = 1.4142
Input: A = 3
Output: 2.1213
方法:解决问题的思路是基于以下数学公式:
Let’s draw a perpendicular from K to down face of cube as Q.
Using Pythagorean Theorem in triangle QKL,
KL2 = QK2 + QL2
l2 = (a/2)2 + (a/2)2
l2 = 2 * (a/2)2
l = a / sqrt(2)
下面是上述方法的实现:
C++
// C++ program for the above approach
#include
using namespace std;
// Function to find the shortest distance
// between the diagonal of a cube and
// an edge skew to it
float diagonalLength(float a)
{
// Stores the required distance
float L = a / sqrt(2);
// Print the required distance
cout << L;
}
// Driver Code
int main()
{
// Given side of the cube
float a = 2;
// Function call to find the shortest
// distance between the diagonal of a
// cube and an edge skew to it
diagonalLength(a);
return 0;
}
Java
// Java program for the above approach
class GFG {
// Function to find the shortest
// distance between the diagonal of a
// cube and an edge skew to it
static void diagonalLength(float a)
{
// Stores the required distance
float L = a / (float)Math.sqrt(2);
// Print the required distance
System.out.println(L);
}
// Driver Code
public static void main(String[] args)
{
// Given side of the cube
float a = 2;
// Function call to find the shortest
// distance between the diagonal of a
// cube and an edge skew to it
diagonalLength(a);
}
}
Python3
# Python3 program for the above approach
from math import sqrt
# Function to find the shortest
# distance between the diagonal of a
# cube and an edge skew to it
def diagonalLength(a):
# Stores the required distance
L = a / sqrt(2)
# Print the required distance
print(L)
# Given side of the cube
a = 2
# Function call to find the shortest
# distance between the diagonal of a
# cube and an edge skew to it
diagonalLength(a)
C#
// C# program for the above approach
using System;
class GFG {
// Function to find the shortest
// distance between the diagonal of a
// cube and an edge skew to it
static void diagonalLength(float a)
{
// Stores the required distance
float L = a / (float)Math.Sqrt(2);
// Print the required distance
Console.Write(L);
}
// Driver Code
public static void Main()
{
// Given side of the cube
float a = 2;
// Function call to find the shortest
// distance between the diagonal of a
// cube and an edge skew to it
diagonalLength(a);
}
}
PHP
Javascript
输出:
1.41421
时间复杂度: O(1)
辅助空间: O(1)
如果您希望与专家一起参加现场课程,请参阅DSA 现场工作专业课程和学生竞争性编程现场课程。