给定一个包含N 个节点的图,其值为P或M 。还给定K对整数作为(x, y)表示图中的边,这样如果a连接到b并且b连接到c那么a和c也将连接。
单个连接的组件称为组。该组可以同时具有P和M值。如果P值大于M值,则该组称为P影响,对于M也类似。如果P和M 的数量相等,则称为中性群。任务是找出P受影响、 M受影响和中立群体的数量。
例子:
Input: Nodes[] = {P, M, P, M, P}, edges[][] = {
{1, 3},
{4, 5},
{3, 5}}
Output:
P = 1
M = 1
N = 0
There will be two groups of indexes
{1, 3, 4, 5} and {2}.
The first group is P influenced and
the second one is M influenced.
Input: Nodes[] = {P, M, P, M, P}, edges[][] = {
{1, 3},
{4, 5}}
Output:
P = 1
M = 2
N = 0
方法:用邻接表构造一个图,从1到N循环,做DFS,检查P和M的计数比较容易。
另一种方法是使用 DSU 稍加修改,大小数组将是成对的,以便它可以保持M 和 P的计数。在这种方法中,不需要构建图,因为合并操作将处理连接的组件。请注意,您应该按大小/等级了解 DSU 以进行优化。
下面是上述方法的实现:
C++
// C++ implementation of the approach
#include
using namespace std;
// To store the parents
// of the current node
vector par;
// To store the size of M and P
vector > sz;
// Function for initialization
void init(vector& nodes)
{
// Size of the graph
int n = (int)nodes.size();
par.clear();
sz.clear();
par.resize(n + 1);
sz.resize(n + 1);
for (int i = 0; i <= n; ++i) {
par[i] = i;
if (i > 0) {
// If the node is P
if (nodes[i - 1] == 'P')
sz[i] = { 0, 1 };
// If the node is M
else
sz[i] = { 1, 0 };
}
}
}
// To find the parent of
// the current node
int parent(int i)
{
while (par[i] != i)
i = par[i];
return i;
}
// Merge funtion
void unin(int a, int b)
{
a = parent(a);
b = parent(b);
if (a == b)
return;
// Total size by adding number of M and P
int sz_a = sz[a].first + sz[a].second;
int sz_b = sz[b].first + sz[b].second;
if (sz_a < sz_b)
swap(a, b);
par[b] = a;
sz[a].first += sz[b].first;
sz[a].second += sz[b].second;
return;
}
// Function to calculate the influenced value
void influenced(vector& nodes,
vector > connect)
{
// Number of nodes
int n = (int)nodes.size();
// Initialization function
init(nodes);
// Size of the connected vector
int k = connect.size();
// Performing union operation
for (int i = 0; i < k; ++i) {
unin(connect[i].first, connect[i].second);
}
// ne = Number of neutal groups
// ma = Number of M influenced groups
// pe = Number of P influenced groups
int ne = 0, ma = 0, pe = 0;
for (int i = 1; i <= n; ++i) {
int x = parent(i);
if (x == i) {
if (sz[i].first == sz[i].second) {
ne++;
}
else if (sz[i].first > sz[i].second) {
ma++;
}
else {
pe++;
}
}
}
cout << "P = " << pe << "\nM = "
<< ma << "\nN = " << ne << "\n";
}
// Driver code
int main()
{
// Nodes at each index ( 1 - base indexing )
vector nodes = { 'P', 'M', 'P', 'M', 'P' };
// Connected Pairs
vector > connect = {
{ 1, 3 },
{ 3, 5 },
{ 4, 5 }
};
influenced(nodes, connect);
return 0;
}
Java
// Java implementation of the approach
import java.io.*;
import java.util.*;
class GFG{
// To store the parents
// of the current node
static ArrayList par = new ArrayList();
// To store the size of M and P
static ArrayList<
ArrayList> sz = new ArrayList<
ArrayList>();
// Function for initialization
static void init(ArrayList nodes)
{
// Size of the graph
int n = nodes.size();
for(int i = 0; i <= n; ++i)
{
par.add(i);
if (i == 0)
{
sz.add(new ArrayList(
Arrays.asList(0, 0)));
}
if (i > 0)
{
// If the node is P
if (nodes.get(i - 1) == 'P')
{
sz.add(new ArrayList(
Arrays.asList(0, 1)));
}
// If the node is M
else
{
sz.add(new ArrayList(
Arrays.asList(1, 0)));
}
}
}
}
// To find the parent of
// the current node
static int parent(int i)
{
while (par.get(i) != i)
{
i = par.get(i);
}
return i;
}
// Merge funtion
static void unin(int a, int b)
{
a = parent(a);
b = parent(b);
if (a == b)
{
return;
}
// Total size by adding number
// of M and P
int sz_a = sz.get(a).get(0) +
sz.get(a).get(1);
int sz_b = sz.get(b).get(0) +
sz.get(b).get(1);
if (sz_a < sz_b)
{
int temp = a;
a = b;
b = temp;
}
par.set(b, a);
sz.get(a).set(0, sz.get(a).get(0) +
sz.get(b).get(0));
sz.get(a).set(1, sz.get(a).get(1) +
sz.get(b).get(1));
return;
}
// Function to calculate the influenced value
static void influenced(ArrayList nodes,
ArrayList> connect)
{
// Number of nodes
int n = nodes.size();
// Initialization function
init(nodes);
// Size of the connected vector
int k = connect.size();
// Performing union operation
for(int i = 0; i < k; ++i)
{
unin(connect.get(i).get(0),
connect.get(i).get(1));
}
// ne = Number of neutal groups
// ma = Number of M influenced groups
// pe = Number of P influenced groups
int ne = 0, ma = 0, pe = 0;
for(int i = 1; i <= n; ++i)
{
int x = parent(i);
if (x == i)
{
if (sz.get(i).get(0) ==
sz.get(i).get(1))
{
ne++;
}
else if (sz.get(i).get(0) >
sz.get(i).get(1))
{
ma++;
}
else
{
pe++;
}
}
}
System.out.println("P = " + pe +
"\nM = " + ma +
"\nN = " + ne);
}
// Driver code
public static void main(String[] args)
{
// Nodes at each index ( 1 - base indexing )
ArrayList nodes = new ArrayList();
nodes.add('P');
nodes.add('M');
nodes.add('P');
nodes.add('M');
nodes.add('P');
// Connected Pairs
ArrayList<
ArrayList> connect = new ArrayList<
ArrayList>();
connect.add(new ArrayList(
Arrays.asList(1, 3)));
connect.add(new ArrayList(
Arrays.asList(3, 5)));
connect.add(new ArrayList(
Arrays.asList(4, 5)));
influenced(nodes, connect);
}
}
// This code is contributed by avanitrachhadiya2155
Python3
# Python3 implementation of the approach
# To store the parents
# of the current node
par = []
# To store the size of M and P
sz = []
# Function for initialization
def init(nodes):
# Size of the graph
n = len(nodes)
for i in range(n + 1):
par.append(0)
sz.append(0)
for i in range(n + 1):
par[i] = i
if (i > 0):
# If the node is P
if (nodes[i - 1] == 'P'):
sz[i] = [0, 1]
# If the node is M
else:
sz[i] = [1, 0]
# To find the parent of
# the current node
def parent(i):
while (par[i] != i):
i = par[i]
return i
# Merge funtion
def unin(a, b):
a = parent(a)
b = parent(b)
if (a == b):
return
# Total size by adding number of M and P
sz_a = sz[a][0] + sz[a][1]
sz_b = sz[b][0] + sz[b][1]
if (sz_a < sz_b):
a, b = b, a
par[b] = a
sz[a][0] += sz[b][0]
sz[a][1] += sz[b][1]
return
# Function to calculate the influenced value
def influenced(nodes,connect):
# Number of nodes
n = len(nodes)
# Initialization function
init(nodes)
# Size of the connected vector
k = len(connect)
# Performing union operation
for i in range(k):
unin(connect[i][0], connect[i][1])
# ne = Number of neutal groups
# ma = Number of M influenced groups
# pe = Number of P influenced groups
ne = 0
ma = 0
pe = 0
for i in range(1, n + 1):
x = parent(i)
if (x == i):
if (sz[i][0] == sz[i][1]):
ne += 1
elif (sz[i][0] > sz[i][1]):
ma += 1
else:
pe += 1
print("P =",pe,"\nM =",ma,"\nN =",ne)
# Driver code
# Nodes at each index ( 1 - base indexing )
nodes = [ 'P', 'M', 'P', 'M', 'P' ]
# Connected Pairs
connect = [ [ 1, 3 ],
[ 3, 5 ],
[ 4, 5 ] ]
influenced(nodes, connect)
# This code is contributed by mohit kumar 29
C#
// C# implementation of the approach
using System;
using System.Collections.Generic;
class GFG{
// To store the parents
// of the current node
static List par = new List();
// To store the size of M and P
static List> sz = new List>();
// Function for initialization
static void init(List nodes)
{
// Size of the graph
int n = nodes.Count;
for(int i = 0; i <= n; ++i)
{
par.Add(i);
if (i == 0)
{
sz.Add(new List(){0, 0});
}
if (i > 0)
{
// If the node is P
if (nodes[i - 1] == 'P')
{
sz.Add(new List(){0, 1});
}
// If the node is M
else
{
sz.Add(new List(){1, 0});
}
}
}
}
// To find the parent of
// the current node
static int parent(int i)
{
while (par[i] != i)
{
i = par[i];
}
return i;
}
// Merge funtion
static void unin(int a, int b)
{
a = parent(a);
b = parent(b);
if (a == b)
{
return;
}
// Total size by adding number
// of M and P
int sz_a = sz[a][0] + sz[a][1];
int sz_b = sz[b][0] + sz[b][1];
if (sz_a < sz_b)
{
int temp = a;
a = b;
b = temp;
}
par[b] = a;
sz[a][0] += sz[b][0];
sz[a][1] += sz[b][1];
return;
}
// Function to calculate the influenced value
static void influenced(List nodes,
List> connect)
{
// Number of nodes
int n = nodes.Count;
// Initialization function
init(nodes);
// Size of the connected vector
int k = connect.Count;
// Performing union operation
for(int i = 0; i < k; ++i)
{
unin(connect[i][0], connect[i][1]);
}
// ne = Number of neutal groups
// ma = Number of M influenced groups
// pe = Number of P influenced groups
int ne = 0, ma = 0, pe = 0;
for(int i = 1; i <= n; ++i)
{
int x = parent(i);
if (x == i)
{
if (sz[i][0] == sz[i][1])
{
ne++;
}
else if (sz[i][0] > sz[i][1])
{
ma++;
}
else
{
pe++;
}
}
}
Console.WriteLine("P = " + pe + "\nM = " +
ma + "\nN = " + ne);
}
// Driver code
static public void Main()
{
// Nodes at each index ( 1 - base indexing )
List nodes = new List(){'P', 'M', 'P', 'M', 'P'};
// Connected Pairs
List> connect = new List>();
connect.Add(new List(){1, 3});
connect.Add(new List(){3, 5});
connect.Add(new List(){4, 5});
influenced(nodes, connect);
}
}
// This code is contributed by rag2127
Javascript
P = 1
M = 1
N = 0
时间复杂度: O(N)。
辅助空间:O(N)。
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