掷骰子直到出现 6 的平均概率是多少？
概率也称为可能性，它在可能的事件发生时起作用。实用程序从零到一指定。在数学中，概率很明显可以估计事件发生的可能性。基本上，概率是预期某事发生的范围。
可能性
为了更准确地理解概率，让我们理解一个抛硬币的例子，可能的结果是——正面和反面。发生任何可能事件的可能性为 1/2。由于发生任何可能事件的可能性相同，因此发生任何有利事件的可能性相同，在这种情况下，它是 1/2。
概率公式
P(A) = {Number of affair A} ⁄ {Total number of affair}
骰子
骰子是一个小块，其边界上有 1 到 6 个标记或颜色，在游戏中用于给出随机整数。骰子是可投掷的小块，具有可检测的边界，可以在相应的图形中停止。它们被流传下来以使各自的人物站立起来，通常作为备牌游戏以及骰子游戏、棋盘游戏、角色扮演游戏和机会游戏的一部分。
通常的骰子是一个块，其六个面中的每一个都可以用从 1 到 6 的不同整数来检测。当可投掷或滚动时，骰子会暂停，在其较高的一侧显示一个从 1 到 6 的随机数，每个事件发生的可能性相同。骰子也可能有凹面或不等的形状，并且可能有明显的数字或字符而不是坑。填充骰子被吸引来有利于某些结果而不是其他结果，以用于突破或放松。
掷骰子直到出现 6 的平均概率是多少？
解决方案：
(5/6)n – 1 is the probability that one rolls any other number at least n times until rolling a six. Setting this to 1/2 gives,
n = -1/log2(5/6) + 1
This is the median of the diffusion: the arithmetical value splitting the excessive half of the diffusion from the lower half.
It is not the mean (standard).
类似问题
问题 1：如果一个公平的 6 面骰子被掷了 3 次，恰好出现一个 3 的概率是多少？
解决方案：
Total ways in which a 6-sided die can be thrown three times = 6 × 6 × 6 = 216
To get precisely one 3, there are three ways,
A 3 on the first throw and non 3 on other two throw. This can be done in 1 × 5 × 5 = 25 ways.
The 3 could be on the second or third throw too. So total likely results = 25 × 3 = 75
Required Probability = 75/216 = 25/72
问题 2：如果一个公平的 6 面骰子被掷了两次，恰好出现一个 4 的概率是多少？
解决方案：
Total ways in which a 6-sided die can be thrown two times = 6 × 6 = 36
To get precisely one 4, there are two ways,
A 4 on the first throw and non 4 on other throw. This can be done in 1 × 5 = 5 ways.
The 4 could be on the second throw too. So total likely results = 5 × 2 = 10
Required Probability = 10/36 = 5/18
问题 3：如果你掷两次公平的六面骰子，两次得到相同数字的概率是多少？
解决方案：
There are six possible numerals that can be thrown twice. For a precise number, say 1, the chances of throwing it twice is equal to,
[1/61st roll] × [1/62nd roll] = [1/36] (by the rule of the product).
Since this can occur for 2, 3, 4, 5, 6, as well as for 1,
The probability of throwing the same number twice is
6 × 1/6 × 1/6 = 1/6
问题 4：如果一个公平的 6 面骰子被掷了 3 次，恰好掷出一个 3 的概率是多少？
解决方案：
Total ways in which a 6 sided die can be thrown three times = 6 × 6 × 6 = 216
to get precisely one 3, there are three ways,
A 3 on the first throw and non 3 on other two throws. This can be done in 1 × 5 × 5 = 25 ways.
The 3 could be on the second or third throw too. So total likely events = 25 × 3 = 75
Required probability = 75/216
= 25/72
问题 5：掷骰子时连续出现 6 到 3 次的概率是多少？
解决方案：
Probability of an affair = (number of favourable event) / (total number of event).
P(B) = {Number of affair B } ⁄ {Total number of affair}.
Probability of occurring 6 = 1/6
Throwing a dice is an free event, it is not dependent on how many times it’s been thrown.
Probability of occurring 6 three times in a row = probability of occurring 6 first time × probability of occurring 6 second time × probability of occurring 6 third time.
Probability of occurring 6 three times in a row = (1/6) × (1/6) × (1/6) = 1/216.
Hence, the probability of occurring 6 three times in a row is 0.463%.