掷骰子得到小于 2 的数字的概率是多少？

在日常生活中，当人们对某些事情不确定时，通常会使用“可能”这个词。例如，大概，印度可能会赢得今天的比赛。印度可能会赢或输，或者这场比赛可能是平局。这种类型的陈述导致事件的不确定性。概率一词由“可能”一词组成，这意味着当人们不确定事件是否发生时。人们有一个适当的方法来找出本文将讨论的概率。

概率中使用的术语

• 随机实验：在随机实验中，我们无法提前预测结果。例如，如果我们抛硬币，我们无法预测头部会出现，尾部也可能出现。
• 事件：实验的某些结果的集合称为事件。
• 样本空间：它是所有可能结果的集合。假设掷出一个骰子，则可能的结果是 1、2、3、4、5 或 6。记为 S。S = (1, 2, 3, 4, 5, 6)
• 掷骰子：骰子是一个实心立方体。它有 6 个正方形面。六个面用 1、2、3、4、5、6 个点标记。当掷出公平的骰子时，可能的总结果是 1、2、3、4、5 或 6。所以所有这些数字都称为样本空间。

可能性

The probability of an event is defined as the ratio of favorable outcomes to the sample space or total outcomes. We represent it by ‘P’.

Probability of an event (P) = ( Number of Favourable outcomes) / (Total number possible outcomes)

掷骰子得到小于 2 的数字的概率是多少？

解决方案：

Concept: To solve the given problem, follow the steps given below.

Step 1: First of all find out all possible outcomes of the given event. Represent it by S.

Step 2: Specify the number of favorable outcomes.

Step 3: Use the formula, Probability of an event = (Favorable outcomes) / (Total number of possible outcomes)

Step 4: Simplify and get the final answer.

When a dice is rolled, all possible outcomes are 1, 2, 3, 4, 5, 6.

We call it as sample space, S = (1, 2, 3, 4, 5, 6)

So total number of possible outcomes = 6

Favorable outcome (Required outcome) = 1

(Only 1 is smaller than 2, remaining number is greater than 2 so we will not consider them as favorable outcomes.)

So total number of favorable outcomes = 1

Probability = (Total number of favorable outcomes)/(Total number of possible outcomes)

Probability = 1/6 

So, the probability of the given statement is 1/6.

类似问题

问题 1：骰子掷出大于 4 的数字的概率是多少？

解决方案：

When a dice is rolled, all possible outcomes are 1, 2, 3, 4, 5, 6.

S = (1, 2, 3, 4, 5, 6)

Number of possible outcomes, n(S) = 6

Favorable outcomes = (5, 6)

(Only 5 and 6 is greater than 4, so these two will be favorable cases)

Number of favorable outcomes, n(F) = 2

Probability = (Number of favorable outcomes)/(Number of total outcomes)

Probability = 2/6

 =1/3

So, the probability of the given statement is 1/3.

问题2：骰子掷出奇数的概率是多少？

解决方案：

 When a dice is rolled, all possible outcomes are 1, 2, 3, 4, 5, 6.

 S = (1, 2, 3, 4, 5, 6) 

 Number of possible outcomes, n(S) = 6

 Favorable outcomes = (1, 3, 5)

 (Only 1, 3, 5 are the odd number obtained when a dice is rolled)

 Total number of favorable outcomes, n(F) = 3

 Probability = (Number of favorable outcomes)/(Number of total outcomes)

 Probability = 3/6 

 = 1/2

 So, the required probability is 1/2.