门| GATE CS Mock 2018 |第 57 题

这是一道来自 GATE CS Mock 2018 的编程题，要求实现一个门类 Gate 和一个分支门类 OrGate 继承 Gate。我们需要实现以下功能：

1. Gate 类需要实现一个 performGateLogic() 方法;
2. OrGate 类需要继承 Gate 类，重载 performGateLogic() 方法并实现与门的逻辑;
3. Gate 类需要包含前一个门（pinA）和后一个门（pinB）的引用，如果没有前一个门时，pinA 可设置为 None，如果没有后一个门，pinB 可设置为 None；
4. Gate 类需要包含一个 label 属性，用于在多门电路中标识门的位置。

以下是代码骨架，您需要对其进行完善：

class LogicGate:

    def __init__(self, n):
        self.label = n
        self.output = None

    def getLabel(self):
        return self.label

    def getOutput(self):
        self.output = self.performGateLogic()
        return self.output

    def performGateLogic(self):
        pass


class BinaryGate(LogicGate):

    def __init__(self, n):
        LogicGate.__init__(self, n)

        self.pinA = None
        self.pinB = None

    def getPinA(self):
        if self.pinA == None:
            return int(input("Enter Pin A input for gate " + self.getLabel()+"-->"))
        else:
            return self.pinA.getFrom().getOutput()

    def getPinB(self):
        if self.pinB == None:
            return int(input("Enter Pin B input for gate " + self.getLabel()+"-->"))
        else:
            return self.pinB.getFrom().getOutput()

    def setNextPin(self, source):
        if self.pinA == None:
            self.pinA = source
        else:
            if self.pinB == None:
                self.pinB = source
            else:
                raise RuntimeError("Error: NO EMPTY PINS")


class AndGate(BinaryGate):

    def __init__(self, n):
        BinaryGate.__init__(self, n)

    def performGateLogic(self):
        a = self.getPinA()
        b = self.getPinB()
        if a==1 and b==1:
            return 1
        else:
            return 0


class OrGate(BinaryGate):

    def __init__(self, n):
        BinaryGate.__init__(self, n)

    def performGateLogic(self):
        # 在这里实现或门的逻辑
        pass


class UnaryGate(LogicGate):

    def __init__(self, n):
        LogicGate.__init__(self, n)

        self.pin = None

    def getPin(self):
        if self.pin == None:
            return int(input("Enter Pin input for gate " + self.getLabel()+"-->"))
        else:
            return self.pin.getFrom().getOutput()

    def setNextPin(self, source):
        if self.pin == None:
            self.pin = source
        else:
            raise RuntimeError("Error: NO EMPTY PINS")


class NotGate(UnaryGate):

    def __init__(self, n):
        UnaryGate.__init__(self, n)

    def performGateLogic(self):
        if self.getPin():
            return 0
        else:
            return 1


class Connector:

    def __init__(self, fgate, tgate):
        self.fromgate = fgate
        self.togate = tgate

        tgate.setNextPin(self)

    def getFrom(self):
        return self.fromgate

    def getTo(self):
        return self.togate

希望您可以成功完成这道编程题！