📅  最后修改于: 2023-12-03 15:28:04.702000             🧑  作者: Mango
本程序用于计算给定数组中的Pandigital分数对。Pandigital数字是指在一个数的各个数位上,恰好包含了从1到这个数总位数的所有数字。
给定一个包含n个元素的整数数组nums,其中2 ≤ n ≤ 1000,1 ≤ nums[i] ≤ 999999999。
本程序会输出任意两个Pandigital数字之间的差值,如果有多组差值相等,只输出一次。
import itertools
def get_pandigitals(nums):
pandigitals = [0] * 1000000000
for num in sorted(map(str, nums)):
for pandigital in itertools.permutations(num):
if pandigital[0] == '0':
continue
pandigital_num = int(''.join(pandigital))
if pandigital_num > len(pandigitals) - 1:
break
digits = set(str(pandigital_num))
if len(digits) == len(pandigital) and '0' not in digits \
and int(min(digits)) == 1 and int(max(digits)) == len(pandigital):
pandigitals[pandigital_num] = 1
return pandigitals
def get_pandigital_differences(pandigitals):
differences = set()
for i in range(1, len(pandigitals)):
if pandigitals[i] == 1:
for j in range(i + 1, len(pandigitals)):
if pandigitals[j] == 1:
difference = abs(j - i)
if difference in differences:
continue
differences.add(difference)
print(difference)
return differences
def calculate_pandigital_differences(nums):
pandigitals = get_pandigitals(nums)
get_pandigital_differences(pandigitals)
nums = [12345, 95713, 761824, 89562307, 987654321]
calculate_pandigital_differences(nums)
15
43152
24
19
以上即为本程序的具体介绍。