📅  最后修改于: 2023-12-03 14:56:42.418000             🧑  作者: Mango
这个主题涉及到多项式乘法的简化。给定两个多项式,我们需要找到它们的乘积并对乘积进行简化。
我们可以使用以下算法步骤来求解:
在Python中,我们可以使用NumPy和SymPy库来计算多项式的乘积和简化:
import numpy as np
from sympy import *
def simplify_polynomial(polynomial1, polynomial2):
# Convert polynomials to arrays of coefficients and exponents
poly1 = Poly(polynomial1)
coeffs1 = poly1.coeffs()
exponents1 = poly1.monoms()
poly2 = Poly(polynomial2)
coeffs2 = poly2.coeffs()
exponents2 = poly2.monoms()
# Multiply each term of the two polynomials
products = []
for i in range(len(coeffs1)):
for j in range(len(coeffs2)):
product = coeffs1[i] * coeffs2[j]
# Multiply variable exponents
new_exponents = [exponents1[i][k] + exponents2[j][k] for k in range(len(exponents1[i]))]
products.append((product, new_exponents))
# Add up all of the products to get the final simplified polynomial
simplified_polynomial = Poly(0, x, y)
for product in products:
simplified_polynomial += Poly(product[0], x, y, *product[1])
return str(simplified_polynomial)
这个函数需要两个参数:表示两个多项式的字符串(例如“3x^2y + 9xy^2 - 12y^3”)。它返回一个字符串,该字符串包含简化的多项式,例如“108x^4y - 9x^3y^2 - 81x^2y^3 + 54xy^4 + 36y^5”。
下面是返回该函数的markdown代码片段:
```python
import numpy as np
from sympy import *
def simplify_polynomial(polynomial1, polynomial2):
# Convert polynomials to arrays of coefficients and exponents
poly1 = Poly(polynomial1)
coeffs1 = poly1.coeffs()
exponents1 = poly1.monoms()
poly2 = Poly(polynomial2)
coeffs2 = poly2.coeffs()
exponents2 = poly2.monoms()
# Multiply each term of the two polynomials
products = []
for i in range(len(coeffs1)):
for j in range(len(coeffs2)):
product = coeffs1[i] * coeffs2[j]
# Multiply variable exponents
new_exponents = [exponents1[i][k] + exponents2[j][k] for k in range(len(exponents1[i]))]
products.append((product, new_exponents))
# Add up all of the products to get the final simplified polynomial
simplified_polynomial = Poly(0, x, y)
for product in products:
simplified_polynomial += Poly(product[0], x, y, *product[1])
return str(simplified_polynomial)