功和能量的区别

工作：工作可能是一种能量转移。每当您走路时，您都在底部工作，因此每当您击败底部时，底部都会对您产生影响。此外，它必须在所施加的力的帮助下在选定方向上移动一段距离才能被视为工作。这意味着劳动力的概念取决于流离失所。为了使工作发生，必须有从一个地方到另一个地方的力和运动。 “工作”一词最早由加斯帕德·科里奥利(Gaspard Coriolis)提出。他是法国数学家。他在 1826 年创造了这个词。物理学的 SI 单位是焦耳。

工作公式

$\begin{matrix} W = \bigtriangleup KE \\ KE = \frac{1}{2} mv^{2} \\ W = F \bigtriangleup r \cos \Theta \end{matrix}$

能量：能量可以定义为对某物做功能力的度量。它不是物质。能量可以以多种形式存储和测量。它也被称为在一定距离内起作用的力。能量处理物体做功的能力。物理的 SI 单位是焦耳。

能量公式

$E_{k} = \frac{1}{2} mv^{2}$
Here,
E_k = kinetic energy of object

m = mass of object

v = speed of object

 

下表列出了功和能量之间的差异：

S.No	WORK	ENERGY
1	Work is the ability to supply force and a change in distance to an object.	Energy is the ability to supply or create work.
2	There is a parallel relationship between the force components and displacement	Energy is that the results of the work performed
3	The action did on the thing causing some displacement	It is described as a property of a system
4	Scalar units.	Scalar units.
5	Work = force X distance	There are various equations depending upon the kinds of energy
6	If the applied force is within the same direction of the displacement than work is positive	The is not any direction component here because it may be a scalar quantity
7	It the applied force is within the other way of the displacement that employment is negative	Then also there’ll be no direction component here because it may be a scalar quantity
8	Work was only utilized in 1826	Energy was coined in 4 BC

工作和能量的示例问题

问题1. 如果用 30 N 的力将 2kg 的负载提升到 10m 的高度(g = 10ms-2)，那么计算此过程中所做的功?

解决方案：

Given, Force in lifting mg = 30 N ; height = 10 m

Work done W = ?

W = F.S (or) mgh

= 30×10

W = 300 J  

Hence the answer is 300J

问题 2. 计算如果 10 N 的力作用在物体上并显示 2 m 的位移所做的功?

解决方案：

Given, F (Force) = 10 N,

d (Displacement) = 2 m,

W (Work done) = F × d

= 10 N × 2 m

= 20 Nm.

问题 3. 静止时质量为 10kg 的物体受到 16N 的力。在 10 s 的顶部找到 KE。

解决方案：

Mass m = 10 kg

Force F = 16 N

time t = 10 s

a = F/m:fl:1.6ms”

10kg

we know v = u + at

Kinetic energy KE : 1/2mv^2

0.5 x 10 x 16 x 16

1280J

问题 4：将质量为 5kg 的物体以 1000 J 的 KE 垂直抛起。如果重力加速度为 10ms-2，请找出 KE 为第一个值一半时的峰值。

解决方案：

Mass m = 5kg

K.E E = 1000J

g = 10m s-2

At a height ‘h’, mgh = E/2

5x10xh = 1000/2

h = 500/50

h = 10m