实现火焰游戏的程序
火焰是一个流行的游戏，以首字母缩写命名：朋友，恋人，深情，婚姻，敌人，兄弟姐妹。该游戏无法准确预测某个人是否适合您，但与您的朋友一起玩会很有趣。
这个游戏有两个步骤：
- 取这两个名字。
- 删除常见字符及其各自的常见情况。
- 获取剩余字符数。
- 以 FLAMES 字母为 [“F”, “L”, “A”, “M”, “E”, “S”]
- 使用我们得到的计数开始删除字母。
- 最后一个过程的字母是结果。
例子 ：
Input: Player1 = AJAY, Player2 = PRIYA
Output: Friends说明：在上面给定的两个名称 A 和 Y 是两个名称中出现一次（共同计数）的常见字母，因此我们从两个名称中删除这些字母。现在计算剩下的字母总数，它是 5。现在开始使用我们得到的计数从 FLAMES 中一个一个地删除字母，持续该过程的字母就是结果。
计数以逆时针循环方式进行。
FLAMES
counting starts from F, E is at 5th count so we remove E and start counting again but this time start from S.
FLAMS
M is at 5th count so we remove M and counting starts from S.
FLAS
S is at 5th count so we remove S and counting start from F.
FLA
L is at 5th count so we remove L and counting starts from A.
FA
A is at 5th count so we remove A. now we have only one letter is remaining so this is the final answer.
F
So, the relationship is F i.e. Friends .
方法：需要三个计数器，两个用于初始化为零的名称，一个用于初始化为 5 的火焰。使用三个字符串，两个用于名称，一个用于已经存储了 FLAMES 的位置。这里程序首先计算名字中的字母数量，然后计算第二名字中的字母数量，然后在使用 strlen 将它们存储到整数变量中之后，为每个名字运行一个 for 循环以计算常见字母。然后通过使用嵌套的 if-else 来取消每个名称中的字母，该名称由字符串表示。再次重复 for 循环以继续此过程。因此，计数器旋转并指向 FLAMES 中的每个字母。随着字母被取消，循环再次运行。然后对于每个字母，使用 If else 语句，打印最后一个字母对应的结果。
下面是实现：
C++
// C++ program to implement FLAMES game
#include
using namespace std;
// Function to find out the flames result
void flame(char* a, char* b)
{
int i, j, k, l = 1, n, m, sc = 0, tc, rc = 0, fc = 5;
char q[25], w[25], c;
char f[] = "flames";
strcpy(q, a);
strcpy(w, b);
n = strlen(a);
m = strlen(b);
tc = n + m;
for (i = 0; i < n; i++)
{
c = a[i];
for (j = 0; j < m; j++)
{
if (c == b[j])
{
a[i] = -1;
b[j] = -1;
sc = sc + 2;
break;
}
}
}
rc = tc - sc;
for (i = 0;; i++)
{
if (l == (rc))
{
for (k = i; f[k] != '\0'; k++)
{
f[k] = f[k + 1];
}
f[k + 1] = '\0';
fc = fc - 1;
i = i - 1;
l = 0;
}
if (i == fc)
{
i = -1;
}
if (fc == 0)
{
break;
}
l++;
}
// Print the results
if (f[0] == 'e')
cout << q <<" is ENEMY to " << w;
else if (f[0] == 'f')
cout << q <<" is FRIEND to "< C
// C program to implement FLAMES game
#include
#include
// Function to find out the flames result
void flame(char* a, char* b)
{
int i, j, k, l = 1, n, m, sc = 0, tc, rc = 0, fc = 5;
char q[25], w[25], c;
char f[] = "flames";
strcpy(q, a);
strcpy(w, b);
n = strlen(a);
m = strlen(b);
tc = n + m;
for (i = 0; i < n; i++) {
c = a[i];
for (j = 0; j < m; j++) {
if (c == b[j]) {
a[i] = -1;
b[j] = -1;
sc = sc + 2;
break;
}
}
}
rc = tc - sc;
for (i = 0;; i++) {
if (l == (rc)) {
for (k = i; f[k] != '\0'; k++) {
f[k] = f[k + 1];
}
f[k + 1] = '\0';
fc = fc - 1;
i = i - 1;
l = 0;
}
if (i == fc) {
i = -1;
}
if (fc == 0) {
break;
}
l++;
}
// Print the results
if (f[0] == 'e')
printf("%s is ENEMY to %s ", q, w);
else if (f[0] == 'f')
printf("%s is FRIEND to %s ", q, w);
else if (f[0] == 'm')
printf("%s is going to MARRY %s", q, w);
else if (f[0] == 'l')
printf("%s is in LOVE with %s ", q, w);
else if (f[0] == 'a')
printf("%s has more AFFECTION on %s ", q, w);
else
printf("%s and %s are SISTERS/BROTHERS ", q, w);
}
// Driver code
int main()
{
char a[] = "AJAY";
char b[] = "PRIYA";
flame(a, b);
} Python3
# Python3 program to implement FLAMES game
# Function to find out the flames result
def flame(a, b):
l, sc = 1, 0
rc, fc = 0, 5
f = "flames"
f = [i for i in f]
q = "".join(a)
w = "".join(b)
# print(q, w)
n = len(a)
m = len(b)
tc = n + m
for i in range(n):
c = a[i]
for j in range(m):
if (c == b[j]):
a[i] = -1
b[j] = -1
sc = sc + 2
break
rc = tc - sc
i = 0
while (i):
if (l == (rc)):
for k in range(i,len(f)):
f[k] = f[k + 1]
f[k + 1] = '\0'
fc = fc - 1
i = i - 1
l = 0
if (i == fc):
i = -1
if (fc == 0):
break
l += 1
i += 1
# Print the results
if (f[0] == 'e'):
print(q, "is ENEMY to", w)
elif (f[0] == 'f'):
print(q, "is FRIEND to", w)
elif (f[0] == 'm'):
print(q, "is going to MARRY", w)
elif (f[0] == 'l'):
print(q, "is in LOVE with", w)
elif (f[0] == 'a'):
print(q, "has more AFFECTION on", w)
else:
print(q, "and", w, "are SISTERS/BROTHERS ")
# Driver code
a = "AJAY"
b = "PRIYA"
a = [i for i in a]
b = [j for j in b]
# print(a,b)
flame(a, b)
# This code is contributed by Mohit KumarJavascript
AJAY is FRIEND to PRIYA