当两个骰子同时掷出时，总共可能的结果是多少？
概率的另一个词是可能性。这是一个机会数学，处理随机事件的发生。该值从零到一表示。在数学中，引入了概率来预测事件发生的可能性。概率的含义基本上是预期某事发生的范围。
- 频率解释：概率被认为是对长期运行各自频率的数学上合适的估计。
- 主观解释：概率陈述表明某些人对事件可能发生的确定程度的信念。
为了更准确地理解概率，以掷骰子为例：
可能的结果是：1、2、3、4、5 和 6。得到任何可能结果的概率是 1/6。由于发生任何事件的可能性是相同的，因此在这种情况下获得任何可能数字的机会均等，它是 1/6 或 50/3%。
概率公式
因为概率是结果的可能性。因此，它基本上是一个比率。用恰当的话来说，可以说概率是预期结果与结果总数的比率。
Probability of an event = {Number of ways it can occur} ⁄ {Total number of outcomes}
P(A) = {Number of ways A occurs} ⁄ {Total number of outcomes}
让我们看一下概率中两种重要的事件类型。它们是同样可能的事件和互补事件，
- 同等可能事件：掷骰子后，获得任何可能事件的概率为 1/6。由于该事件是同等可能的事件，因此在这种情况下有可能获得任何数字，它要么是公平掷骰子的 1/6。
- 补充事件：只有两个结果的概率或可能性是一个事件会发生与否。就像一个人会吃或不吃，买车或不买车等都是互补事件的例子。
当两个骰子同时掷出时，总共可能的结果是多少？
解决方案：
A standard die has six sides numbering 1, 2, 3, 4, 5, and 6. If the die is fair, then each of these outcomes is equally likely event. Since there are six possible outcomes. The probability of getting any side of the die is 1/6. The probability of obtaining a 1 is 1/6, the probability of obtaining a 2 is 1/6, and so on.
The number of total possible outcomes is equal to the total numbers of the first die (6) multiplied by the total numbers of the second die (6), which is 36. So, the total possible outcomes when two dice are thrown together is 36.
The equally likely outcomes of rolling two dice are shown in the table below: 1 2 3 4 5 6 1 (1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6) 2 (2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6) 3 (3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6) 4 (4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6) 5 (5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6) 6 (6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)
类似问题
问题 1：当三个骰子放在一起时，总共可能的结果是什么？
解决方案：
A standard die has six sides numbering 1, 2, 3, 4, 5, and 6. If the die is fair, then each of these outcomes is equally likely event. Since there are six possible outcomes, the probability of getting any side of the die is 1/6. The probability of obtaining a 1 is 1/6, the probability of obtaining a 2 is 1/6, and so on.
The number of total possible outcomes is equal to the total numbers of the first die (6) multiplied by the total numbers of the second die (6)multiplied by the total number of the third die(6), which is 216. So, the total possible outcomes when three dies are thrown together is 216.
问题 2：当四个骰子放在一起时，总共可能的结果是什么？
解决方案：
A standard die has six sides numbering 1, 2, 3, 4, 5, and 6. If the die is fair, then each of these outcomes is equally likely event. Since there are six possible outcomes, the probability of getting any side of the die is 1/6. The probability of obtaining a 1 is 1/6, the probability of obtaining a 2 is 1/6, and so on.
The number of total possible outcomes is equal to the total numbers of the first die (6) multiplied by the total numbers of the second die (6)multiplied by the total number of the third die(6)multiplied by the total number of the fourth die(6), which is 1296.
So, the total possible outcomes when four dies are thrown together is 1296.