用两个骰子掷出 6 或 12 有多少种方法?
概率也被称为机会数学。这意味着可能性,即处理可能发生的事件。该值从零到一。在数学中,概率已明确用于估计事情发生的可能性。基本上,概率是预期某事发生的程度。
可能性
为了更准确地理解概率,让我们来理解一个掷骰子的例子,可能的结果是——1、2、3、4、5和6。发生任何可能的事情的概率是1/6。由于发生任何事情的可能性相同,因此发生任何有利事情的可能性相同,在这种情况下,它是两个 1/6 或 50/3。
概率公式
P(A) = {Number of favourable affair to A} ⁄ {Total number of affair}
骰子
骰子是一块微小的砖块,其边缘有 1 到 6 个点或污点,用于在游戏中给出随机数。骰子是一种可投掷的微小砖块,具有明显的边缘,可以停在几个数字中。它们被流传下来以产生随机数字,通常作为备牌游戏以及骰子游戏、棋盘游戏、角色扮演游戏和机会游戏的一部分。
通常的骰子是一个立方体,它的六个面中的每一个都可以用从一到六个不同数量的图形来感知。当可投掷或滚动时,骰子会暂停,在其较高的一侧显示一个从 1 到 6 的随机数,每个事件发生的可能性相同。骰子也可能有凹面或不等的形状,并且可能有明显的数字或字符而不是坑。填充骰子被吸引来有利于某些结果而不是其他结果,以用于突破或放松。
用两个骰子掷出 6 或 12 有多少种方法?
解决方案:
There are five ways to have 6 and only one way to obtain 12 on two dices.
Explanation:
When two dices are rolled, there are five possibilities of rolling a sum of 6.
These are (1, 5), (2, 4), (3, 3), (4, 2), (5, 1)
And one possibility of rolling a sum of 12.
These are (6, 6).
类似问题
问题 1:用两个骰子掷出 7 或 11 有多少种方法?
解决方案:
There are six ways to have 7 and two ways one can have 11 on two dices.
Explanation:
When two dices are rolled, there are six possibilities of rolling a sum of 7.
These are (2, 5), (1, 6), (3, 4), (4, 3), (5, 2), (6, 1).
And two possibilities of rolling a sum of 11.
These are (5, 6), (6, 5).
问题 2:用两个骰子掷出 5 或 10 有多少种方法?
解决方案:
There are four ways to have 5 and three ways one can have 10 on two dices.
Explanation:
When two dices are rolled, there are four possibilities of rolling a sum of 5.
These are (1, 4), (2, 3), (3, 2), (4, 1).
And three possibilities of rolling a sum of 10.
These are (4, 6), (5, 5), (6, 4).
问题 3:用两个骰子掷出 4 或 9 有多少种方法?
解决方案:
There are three ways to have 4 and four ways to have 9 on two dices.
Explanation:
When two dices are rolled, there are three possibilities of rolling a sum of 4.
These are (1, 3), (2, 2), (3, 1).
And four possibilities of rolling a sum of 9.
These are (3, 6), (4, 5), (5, 4), (6, 3).
问题 4:用两个骰子掷出 3 或 8 有多少种方法?
解决方案:
There are two ways to have 3 and five ways one can have 8 on two dices.
Explanation:
When two dices are rolled, there are two possibilities of rolling a sum of 3.
These are (1, 2), (2, 1).
And five possibilities of rolling a sum of 8.
These are (2, 6), (3, 5), (4, 4), (6, 2), (5, 3).