掷一次骰子得到 6 的概率是多少？
概率是对随机事件发生可能性的估计，取值范围为 0 到 1。确定事件的概率始终为 1，永远不会发生的事件的概率为零。您可能还想知道气象站如何预测今天会下雨，以及板球队的输赢是如何产生的。概率论有助于找到所有此类问题的答案。概率处理随机实验发生的机会。
获得结果的概率定义为事件发生的次数与试验总数的比率。
P(A) =（事件 A 发生的次数/试验总数）
让我们试试这个公式来计算掷出一个骰子的所有可能结果的概率。假设你掷骰子，有六种可能的结果。它们是 1、2、3、4、5 和 6。骰子得到 1 的概率是 P(1) = 1/6。同样，得到 2、3、4、5、6 的概率也是 1/6。
与概率相关的术语
- 实验：实验是可以无限重复的试验，每次试验都会得到可能的结果。
- 样本空间：试验或实验的所有可能值都可以用一个集合来表示，这个集合称为样本空间。
- 事件：已执行实验的一组有利结果称为事件，或者也可以说它是实验样本空间的子集。
概率加法规则
如果有两个事件 A 和 B 的概率分别为 P(A) 和 P(B)。然后，根据概率的加法规则，组合概率将由下面给出的公式计算。
P(AUB) = P(A) + P(B) – P(A∩B)
掷一次骰子得到 6 的概率是多少？
解决方案：
To find the probability of getting 6 on the face when a die is rolled. We can do this by using the formula of probability.
P(E) = (Number of times event occurs)/(Total number of trials)
Sample space of possible outcomes on rolling a die is S = {1, 2, 3, 4, 5, 6}
If event E is the probability of getting 6 as the outcome on rolling a die.
Number of times event occurs [n(E)] = 1
Total number of trials [n(S)] = 6
P(E) = 1/6 = 0.167
类似问题
问题 1：掷骰子得到 5 的概率是多少？
解决方案：
To find the probability of getting 5 on the face when a die is rolled. We can do this by using the formula of probability.
P(E) = (Number of times event occurs)/(Total number of trials)
Sample space of possible outcomes on rolling a die is S = {1, 2, 3, 4, 5, 6}
If event E is the probability of getting 5 as the outcome on rolling a die.
Number of times event occurs [n(E)] = 1
Total number of trials [n(S)] = 6
P(E) = 1/6 = 0.167
问题 2：掷骰子时得到 2 的概率是多少？
解决方案：
To find the probability of getting 2 on the face when a die is rolled. We can do this by using the formula of probability.
P(E) = (Number of times event occurs)/(Total number of trials)
Sample space of possible outcomes on rolling a die is S = {1, 2, 3, 4, 5, 6}
If event E is the probability of getting 2 as the outcome on rolling a die.
Number of times event occurs [n(E)] = 1
Total number of trials [n(S)] = 6
P(E) = 1/6 = 0.167
问题 3：掷骰子得到 6 或 3 的概率是多少？
解决方案：
To find the probability of getting 6 or 3 on the face when a die is rolled. We can do this by using the formula of probability.
P(E) = (Number of times event occurs)/(Total number of trials)
Sample space of possible outcomes on rolling a die is S = {1, 2, 3, 4, 5, 6}
If event E is the probability of getting 6 or 2 as the outcome on rolling a die.
Number of times event occurs [n(E)] = 2
Total number of trials [n(S)] = 6
P(E) = 2/6 = 1/3 = 0.333…