正方形周长的公式是什么？

正方形是相邻边长度相等的矩形。这意味着它是一个四边形，所有边的长度都相等。正方形中的每个角都是直角。

特性：

• 正方形的四个边长相等
• 正方形的对角线相等
• 正方形的对角线以直角相互平分
• 正方形的四个角都是直角

正方形的周长

周长是指多边形所有边的总和。对于正方形，它将是其四个相等边的总和，即边长的四倍。

让我们考虑一个正方形，每边的长度等于“a”个单位。

Perimeter = Sum of all sides of square = a + a + a + a = 4a units

每边长一个单位的正方形

因此，每边长度等于“a”单位的正方形的周长由 4a 给出。

示例问题

问题1：求边长为5厘米的正方形的周长。

解决方案：

Length of each side of the square = 5 cm

Perimeter of the square = sum of all sides = 5 + 5 + 5 + 5 = 20 cm

Thus, perimeter of square = 20 cm

问题 2：求周长为 48 厘米的正方形的边长。

解决方案：

Given perimeter of the square = 48 cm

Lets length of each side of the square = ‘a’ cm

Therefore, perimeter = 4a cm

Therefore, we can write:

4a = 48 cm

a = 12 cm

Thus, length of each side of square is 12 cm.

问题 3：求对角线长度为 4√2 厘米的正方形的周长。

解决方案：

Given, the length of a diagonal square = 4√2 cm.

Let the length of each side of the square = a cm.

Thus, applying the Pythagoras theorem, the length of diagonal = √(a²+a²) = a√2 cm

So, we can write:

a√2 = 4√2

a = 4 cm

Thus, the perimeter of square = 4a = 4 × 4 = 16 cm

问题 4：给定正方形的周长为 12 厘米，求正方形的相邻边之和。

解决方案：

Given the perimeter of the square = 12 cm

Considering length of each side = ‘a’ cm, the perimeter = 4a cm

Thus, we can write:

4a = 12

a = 3 cm

Since adjacent sides of a square are having the same length, we can write the sum of any adjacent sides of the square = a + a = 2a 

Therefore, the sum of adjacent sides of the square = 2 × 3 = 6 cm