📜  Python Scipy – ndimage.interpolation.geometric_transform()函数

📅  最后修改于: 2022-05-13 01:55:38.285000             🧑  作者: Mango

Python Scipy – ndimage.interpolation.geometric_transform()函数

给定的映射函数用于为输出中的每个点查找输入中的对应坐标

示例 1:

Python3
from scipy import ndimage
 
# importing numpy module for
# processing the arrays
import numpy as np
 
 
# creating an 2 dimensional array with
# 5 * 5 dimensions
a = np.arrange(25).reshape((5, 5))
 
print('a')
print(a)
 
 
# reducing dimensions function
def shift_func(output_coords):
     
    return (output_coords[0] - 0.7, output_coords[1] - 0.7)
 
# performing geometric transform operation
ndimage.geometric_transform(a, shift_func)


Python3
from scipy import ndimage
 
# importing numpy module for
# processing the arrays
import numpy as np
 
 
# create 4 * 4 dim array.
b = np.arrange(16).reshape((4, 4))
 
# reducing dimensions function
def shift_func(output_coords):
 
    return (output_coords[0] - 0.1, output_coords[1] - 0.2)
 
 
ndimage.geometric_transform(b, shift_func)


输出:

示例 2:

蟒蛇3

from scipy import ndimage
 
# importing numpy module for
# processing the arrays
import numpy as np
 
 
# create 4 * 4 dim array.
b = np.arrange(16).reshape((4, 4))
 
# reducing dimensions function
def shift_func(output_coords):
 
    return (output_coords[0] - 0.1, output_coords[1] - 0.2)
 
 
ndimage.geometric_transform(b, shift_func)

输出: