给定数字N ,任务是找到第N个八边形数。
An Octadecagonal number is a class of figurate numbers. It has 18 – sided polygon called Octadecagon. The Nth Octadecagonal number count’s the eighteen number of dots and all other dots are surrounding with a common sharing corner and make a pattern. The first few Octadecagonal numbers are 1, 18, 51, 100, 165, 246, 343 …
例子:
Input: N = 2
Output: 18
Explanation:
The second octadecagonal number is 18.
Input: N = 6
Output: 246
方法:第N个十八进制数由下式给出:
下面是上述方法的实现:
C++
// C++ program to find Nth
// Octadecagonal number
#include
using namespace std;
// Function to find N-th
// Octadecagonal number
int Octadecagonal_num(int n)
{
// Formula to calculate nth
// Octadecagonal number
return (16 * n * n - 14 * n) / 2;
}
// Driver code
int main()
{
int n = 3;
cout << Octadecagonal_num(n) << endl;
n = 10;
cout << Octadecagonal_num(n) << endl;
return 0;
}
Java
// Java program to find Nth
// octadecagonal number
import java.io.*;
import java.util.*;
class GFG{
// Function to find N-th
// octadecagonal number
static int Octadecagonal_num(int n)
{
// Formula to calculate nth
// octadecagonal number
return (16 * n * n - 14 * n) / 2;
}
// Driver code
public static void main(String[] args)
{
int n = 3;
System.out.println(Octadecagonal_num(n));
n = 10;
System.out.println(Octadecagonal_num(n));
}
}
// This code is contributed by coder001
Python3
# Python3 program to find Nth
# octadecagonal number
# Function to find N-th
# octadecagonal number
def Octadecagonal_num(n):
# Formula to calculate nth
# octadecagonal number
return (16 * n * n - 14 * n) / 2
# Driver code
n = 3
print(int(Octadecagonal_num(n)))
n = 10
print(int(Octadecagonal_num(n)))
# This code is contributed by divyeshrabadiya07
C#
// C# program to find Nth
// octadecagonal number
using System;
class GFG{
// Function to find N-th
// octadecagonal number
static int Octadecagonal_num(int n)
{
// Formula to calculate nth
// octadecagonal number
return (16 * n * n - 14 * n) / 2;
}
// Driver code
public static void Main(string[] args)
{
int n = 3;
Console.Write(Octadecagonal_num(n) + "\n");
n = 10;
Console.Write(Octadecagonal_num(n) + "\n");
}
}
// This code is contributed by rutvik_56
Javascript
输出:
51
730
参考: https : //en.wikipedia.org/wiki/Polygonal_number