传热公式
热量是一种从热的东西转移到冷的东西的能量。当我们接触冷的东西时，我们身体的热量就会转移到冷的东西上。热量在不同温度的物体之间传递。当两个物体达到相同的温度时，热量的传递就会停止。
传播热量
当能量从较高温度的物体转移到较低温度的物体时，就会发生热传递。热量是运输中能量的术语。当我们手里拿着冰块时，我们的手掌会感到冰冷。这是由于热量从我们的身体传递到冰块的结果。由于身体的热量散失，我们的手的温度下降，使我们感到寒冷。两个项目之间发生的热传递越快，它们之间的温差就越大。
传热公式
Q = C×m×ΔT
Where,
Q = heat
c = specific heat
m = mass of the body
ΔT = temperature difference
示例问题
问题1：什么是热？
回答
The vibrations of molecules or atoms increase as the temperature of a body rises. These vibrations are then passed from one body part to the next. The amount of energy used to vibrate the molecules in a system is referred to as heat.
It is denoted by Q.
问题 2：确定将 1 kg 铁从 250° C 升至 600° C 所需的热量？
解决方案
Mass, m = 1 Kg,
Specific heat of iron, C = 0.45 Jg−1°C
Also, temperature difference,
ΔT=700°C–250°C
ΔT=450°C
Now applying the heat formula,
c=Q/mΔT
rearranging the formula
Q=mcΔT
Q=1×0.45×103×450
= 20.25 J
问题 3：确定如果将 50 Kg 水从 600°C 冷却到 200°C，会损失多少热能。水的比热为 C=4.2×103JKg -1 °C。
解决方案
Mass of water, m = 50 Kg,
Specific heat of water, C = 4.2×103JKg−1°
Temperature difference,
ΔT=–40°
Heat energy by formula is,
Q = mcΔT
Q = 50×4.2×103×(−400)
Q= – 840 J
问题4：传热的对流方式是什么？
回答
In liquids and gases, heat is transferred through convection. The particles of a liquid or gas move from one location to another to transfer heat in the convection mechanism of heat transmission.
问题 5：重达 5 公斤的系统从初始温度 30ᵒC 加热到最终温度 60ᵒC。计算系统获得的总热量。 (系统比热 = 0.45 kJ/Kg K)
解决方案
The Initial temperature of the system, Ti = 30ᵒC
The Final temperature of the system, Tf = 60ᵒC
Mass of the system, m = 5 kg
The total heat gained by the system can be calculated by using the formula for heat transfer as mentioned above,
Q= c x m x ΔT
Q=5×0.45×30
Q=67.5 J