📅  最后修改于: 2023-12-03 15:42:11.524000             🧑  作者: Mango
This question deals with finding the closest pair of points in a given set of points in two dimensions.
Given a set of n points in a plane, we wish to find a pair of points with the smallest Euclidean distance between them. Write a divide-and-conquer algorithm to find the closest pair of points among a set of n points.
We can solve this problem using a divide-and-conquer algorithm as follows:
The algorithm can be implemented using the following pseudocode:
closestPair(P)
if n <= 3:
return bruteForceClosestPair(P)
mid = n / 2
left = P[:mid]
right = P[mid:]
dL = closestPair(left)
dR = closestPair(right)
d = min(dL, dR)
strip = []
for point in P:
if abs(point.x - mid.x) < d:
strip.append(point)
dstrip = stripClosestPair(strip, d)
return min(d, dstrip)
The bruteForceClosestPair(P)
function returns the closest-pair distance for a set of points using a brute-force algorithm. The stripClosestPair(strip, d)
function returns the closest-pair distance for the points in the strip
that are closer than d
to the dividing line.
The time complexity of the algorithm is O(nlogn) due to the recursive divide-and-conquer approach. The space complexity is O(n) due to the creation of the left
, right
, and strip
arrays.
In this question, we have discussed an algorithm to find the closest pair of points in a given set of points in two dimensions using a divide-and-conquer approach. The time complexity of the algorithm is O(nlogn) and the space complexity is O(n). This algorithm can be useful for applications such as computer vision and robotics that involve finding the closest pairs of points in a two-dimensional space.