以下C程序的输出是什么?
main()
{
char g[] = "geeksforgeeks";
printf("%s", g + g[6] - g[8]);
} (一)极客
(B)怪胎
(C)极客
(D)极客答案： (A)
解释：
char g[] = “geeksforgeeks”;
// g now has the base address string “geeksforgeeks”
// g[6] is ‘o’ and g[1] is ‘e’.
// g[6] – g[1] = ASCII value of ‘o’ – ASCII value of ‘e’ = 8
// So the expression g + g[6] – g[8] becomes g + 8 which is
// base address of string “geeks”
printf(“%s”, g + g[6] – g[8]); // prints geeks 因此，选项(A)是正确的
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