球体体积公式
测量是一门数学学科,涉及对各种几何形式的研究。它还解决了这种几何形状的面积和体积。它是与测量有关的数学领域,例如代数方程在几何形式的面积、体积和其他特征的测量中的表达和应用,而几何是与空间联系有关的数学分支。
领域
球体是几何形状为圆形的三维立体物体。从数学的角度来看,它是一组点的三维组合,这些点由一个等距离的公共点连接。与其他三维形状不同,球体没有顶点或边。它的中心与表面上的所有地方距离相等。换句话说,球体中心与其表面上任何一点之间的距离是相同的。
球体的体积
球体的体积是它在其中占据的空间量。球体是一个三维圆形实心形状,其表面上的所有点都与其中心等距。固定距离称为球体半径,固定点称为球体中心。当圆圈转动时,我们会注意到形式的变化。作为被称为圆的二维物体的旋转的结果,获得了球体的三维形状。
球体的体积公式由下式给出,
V =
where,
R = radius of the sphere
π = 22/7
推导
Using the integration approach, we can simply calculate the volume of a sphere.
Suppose the sphere’s volume is made up of a series of thin circular discs stacked one on top of the other, as drawn in the diagram above. Each thin disc has a radius of r and a thickness of dy that is y distance from the x-axis.
Let the volume of a disc be dV. The value of dV is given by,
dV = (πr2)dy
dV = π (R2 – y2)dy
The total volume of the sphere will be the sum of volumes of all these small discs. The required value can be obtained by integrating the expression from limit -R to R.
So, the volume of sphere becomes,
V =
=
=
=
=
=
This derives the formula for volume of sphere.
示例问题
问题 1. 求一个半径为 9 厘米的球体的体积。
解决方案:
We have, r = 9.
Volume of sphere = 4/3 πr3
= (4/3) (3.14) (9) (9) (9)
= (4) (3.14) (3) (9) (9)
= 3052 cm3
问题 2. 求一个半径为 12 厘米的球体的体积。
解决方案:
We have, r = 12
Volume of sphere = 4/3 πr3
= (4/3) (3.14) (12) (12) (12)
= (4) (3.14) (4) (12) (12)
= 7234.56 cm3
问题 3. 求一个半径为 6 厘米的球体的体积。
解决方案:
We have, r = 6.
Volume of sphere = 4/3 πr3
= (4/3) (3.14) (6) (6) (6)
= (4) (3.14) (2) (6) (6)
= 904.32 cm3
问题 4. 求一个半径为 4 厘米的球体的体积。
解决方案:
We have, r = 4.
Volume of sphere = 4/3 πr3
= (4/3) (3.14) (4) (4) (4)
= (1.33) (3.14) (4) (4) (4)
= 267.27 cm3
问题 5. 求一个直径为 10 厘米的球体的体积。
解决方案:
We have, 2r = 10
=> r = 10/2
=> r = 5
Volume of sphere = 4/3 πr3
= (4/3) (3.14) (5) (5) (5)
= (1.33) (3.14) (5) (5) (5)
= 522.025 cm3
问题 6. 求一个直径为 16 厘米的球体的体积。
解决方案:
We have, 2r = 16
=> r = 16/2
=> r = 8
Volume of sphere = 4/3 πr3
= (4/3) (3.14) (8) (8) (8)
= (1.33) (3.14) (8) (8) (8)
= 2138.21 cm3
问题 7. 求一个直径为 14 厘米的球体的体积。
解决方案:
We have, 2r = 14
=> r = 14/2
=> r = 7
Volume of sphere = 4/3 πr3
= (4/3) (3.14) (7) (7) (7)
= (1.33) (3.14) (7) (7) (7)
= 1432.43 cm3