化简 7x 2 (3x – 9) + 3 并找到 x = 4 和 x = 6 的值
代数表达式,也称为变量表达式,是由常数和变量组合形成的变量项组成的方程。这些组件使用运算连接在一起,例如加法、减法、乘法或除法。每一项中伴随变量的常数称为系数。
对于 x = 4 和 x = 6,求解方程 7x 2 (3x – 9) + 3
解决方案:
⇒ 7x2(3x – 9) + 3
Find the solution for 7x2(3x – 9)
By using distributive law which states that;
a(b – c) = ab – ac
So according to the law
⇒ (7x2 × 3x) – (7x2 × 9)
⇒ 21x3 – 63x2
Therefore,
⇒ 7x2(3x – 9) + 3 = 21x3 – 63x2 + 3
Now we have to solve for the equation
21x3 – 63x2 + 3
Further,
For x = 4,
⇒ 21x3 – 63x2 + 3
⇒ 21 × 43 – 63 × 42 + 3
⇒ 1344 – 1008 + 3
⇒ 336 + 3
⇒ 339
Further,
Now for x = 6,
⇒ 21x3 – 63x2
⇒ 21 × 63 – 63 × 62 + 3
⇒ 2268 + 3
⇒ 2271
Therefore,
The algebraic expression ⇒ 7x2(3x – 9) + 3
For the value of x = 4 is 339
For the value of x = 6 is 2271
示例问题
问题 1. 通过应用合适的代数恒等式,找到 1050 2
解决方案:
By applying the algebraic identity in the question: (a + b)² = a² + 2ab + b²
Thus,
1050 = 1000 + 50
Therefore,
10502 = (1000 + 50)2
Here,
a = 1000
b = 50
(1000 + 50)2 = (1000)² + 2 × 1000 × 50 + (50)²
= 1000000 + 100000 + 2500
Therefore,
10502 = 1102500.
问题 2. 简化 82 + 2×(5x – 7)。对于 x = 2 和 x = -2 的值?
解决方案:
Here we have,
82 + 2 × (5x – 7)
For x = 2
Substitute value of x = 2 in the equation
= 82 + 2 × (5x – 7)
= 82 + (2 × 5x – 2 × 7)
= 82 + (10x – 14)
= 82 + 10x – 14
= 82 – 14 + 10 × 2
= 82 – 14 + 20
= 88
For x = -2
Substitute value of x = -2 in the equation
= 82 + 2 × (5x – 7)
= 82 + (2 × 5x – 2 × 7)
= 82 + (10x – 14)
= 82 + 10x – 14
= 82 – 14 + 10 × (-2)
= 82 – 14 – 20
= 48
问题 3. 简化 24 × 7 + x(365 – 65)。对于 x = 1 和 x = -1 的值
解决方案:
Here we have
24 × 7 + x(365 – 65)
For x = 1
Substitute value of x = 1 in the equation
= 24 × 7 + x(365 – 65)
= 168 + x(365 – 65)
= 168 + 365x – 65x
= 168 + 300x
= 168 + 300 × 1
= 168 + 300
= 468
For x = -1
Substitute value of x = -1 in the equation
= 24 × 7 + x(365 – 65)
= 168 + x(365 – 65)
= 168 + 365x – 65x
= 168 + 300x
= 168 + 300 × (-1)
= 168 – 300
= -132
问题 4. 减去多项式。
(6x + 3) 从 (-8x + 6)
并简化为 x = 4
解决方案:
(6x + 3) from (-8x + 6)
= (-8x + 6) – (6x + 3)
= -8x + 6 – 6x – 3
= -8x -6x + 6 – 3
= -14x + 3
For x = 4
Substitute value of x = 4 in the equation
= -14 × 4 + 3
= -56 + 3
= -53
问题 5. 求解方程 5x 2 (6x – 7) + 5 对于 x = 2 和 x = 4
解决方案:
5x2(6x – 7) + 5
Find the solution for
5x2(6x – 7)
By using distributive law which states that;
a(b – c) = ab – ac
So according to the law
⇒ (5x2 × 6x) – (5x2 × 7)
⇒ 30x3 – 35x2
Therefore,
⇒ 5x2(6x – 7) + 5 = 30x3 – 35x2 + 5
Now we have to solve for the equation
30x3 – 35x2 + 5
Further,
For x = 4,
⇒ 30x3 – 35x2 + 5
⇒ 30 × 43 – 35 × 42 + 5
⇒ 1920 – 560 + 5
⇒ 1360 + 5
⇒ 1365
Further,
Now for x = 6,
⇒ 30x3 – 35x2 + 5
⇒ 30 × 63 – 35 × 62 + 5
⇒ 6480 – 1260 + 5
⇒ 5220 + 5
⇒ 5225
Therefore,
The algebraic expression ⇒ 5x2(6x – 7) + 5
For the value of x = 4 is 1365
For the value of x = 6 is 5225