如何计算骰子概率？
概率也称为可能性，它在可能的事件发生时起作用。实用程序从零到一指定。在数学中，概率很明显可以估计事件发生的可能性。基本上，概率是预期某事发生的范围。
可能性
为了更准确地理解概率，让我们理解一个抛硬币的例子，可能的结果是——正面和反面。发生任何可能事件的可能性为 1/2。由于发生任何可能事件的可能性相同，因此发生任何有利事件的可能性相同，在这种情况下，它是 1/2。
概率公式
P(A) = {Number of affair A} ⁄ {Total number of affair}
骰子
骰子是一个小块，在其边界上有 1 到 6 个标记或色调，在游戏中用于给出随机整数。骰子是可投掷的小块，具有可检测的边界，可以在相应的图形中停止。它们被流传下来以使各自的人物站立起来，通常作为备牌游戏以及骰子游戏，棋盘游戏，角色扮演游戏和机会游戏的一部分。
通常的骰子是一个块，其六个面中的每一个都可以用从 1 到 6 的不同整数来检测。当可投掷或滚动时，骰子会暂停，在其较高的一侧显示一个从 1 到 6 的随机数，每个事件发生的可能性相同。骰子也可能有凹面或不等的形状，并且可能有明显的数字或字符而不是坑。填充骰子被吸引来有利于某些结果而不是其他结果，以用于突破或放松。
如何计算骰子概率？
回答：
- One Dice Rolls
The uncomplicated and easiest case of dice probabilities is the possibility of occurring a specific integer with one dice. In probability, the primary act is that one must compute it by looking at the number of likely events in collation to the desired events.
Dice presents six likely events. Furthermore, the attentiveness of the independent would be only for one affair disregarding of the choice of integer. A dice probability calculator would be totally convenient in this regard.
The formula one may use in this case is,
P(A) = {Number of affair to A} ⁄ {Total number of affair}
Therefore, the odds of getting a specific number, if the number is 6, this gives,
Probability = 1 ÷ 6 = 0.167
Probabilities are accessible as numbers between no possibility and reliability. Furthermore, no possibility resembles 0 and reliability resembles 1. An independent can multiply this by 100 to operate a percentage. As a consequence, the possibility of getting 6 on the dice is 16.7%.
- Two or More Dice
The probabilities definitely get a little more complex to work out when two dice are concerned. The calculation of uncommon probabilities takes place when one wish to know the probability of getting two 6s by throwing two dice. Most remarkable, the result of one dice does not rely upon on the result of the other dice.
Unconventional probabilities have the rule that one must multiply the individual probabilities jointly to attain the outcome. Therefore, the formula for this is,
Probability of both = Probability of result one × Probability of result two
- Total Score from Two or More Dice
If an individual wants to know the likelihood of getting a particular total sore by rolling two or more dice, then one must go back to the simple rule.
This simple rule is probability = number of likely result divided by the number of likely results. Again, the use of a dice probability calculator is critical here. Calculating the number of result one is concerned in requires more work. If an individualistic wish a total score of 4 on two dice, then this is attainable by rolling 1 and 3, 3 and 1, or 2 and 2.
Furthermore, the individual must observe the dice individually, 1 on first dice and 3 on other dice is surely different than a 3 on first dice and 1 on the second dice. For rolling a 4, there are three ways to get the result one wishes. Hence, there are 36 likely result. The work out of this is as follows,
Probability = Number of desired outcomes/Number of possible outcomes = 3 ÷ 36 = 0.0833.
The proportion comes out to be 8.33 per cent. Also, 7 is the most favourable outcome for two dice. In addition, there are six ways to attain it. The probability in this case is 6 ÷ 36 = 0.167 = 16.7%.
类似问题
问题 1：求掷两个骰子得到 8 的概率？
回答：
There are 36 total likely results on throwing two dice i.e., 6² = 6 × 6 = 36.
There are 5 total possibility of retrieving a sum of 8 on throwing two dice i.e., (2, 6), (3, 5), (4, 4), (5, 2), (6, 2).
Hence, the probability of retrieve a sum of 8 on throwing two dice is 5/36.
问题 2：Shawn 掷骰子 400 次，他将得到 5 的分数记录为 30 次。可能发生的概率是多少
a) 检索到 5 分？
b) 检索到低于 5 的分数？
解决方案：
a) P (getting a score of 5)
= Number of times getting 5/total times
= 30/400
= 3/40
b) P (getting a score under 5)
= number of times getting under 5/total times
= 370/400
= 37/40
a) P (getting 5) = 3/40
b) P (getting under 5) = /3740
问题 3：如果掷两个骰子，得到 6 和的概率是多少？
解决方案：
When two dice are rolled, n(S) = 36. Let, A be the event of getting a sum of 6. Then,
A = {(3, 3), (2, 4), (4, 2), (1, 5), (5, 1)}
n(A) = 5
Hence, the required probability will be,
P(A) = n(A)/n(S) = 5/36.
问题 4：求掷两个骰子并得到 4 和的概率。
解决方案：
The set of possible outcomes when we roll a die are {1, 2, 3, 4, 5, 6}
So, when two dice are rolled, there are 6 × 6 = 36 chances.
When we roll two dice, the probability of retrieving number 4 is (1, 3), (2, 2), and (3, 1).
So, the number of favorable outcomes = 3
Total number of possibilities = 36
Probability = {Number of likely affair } ⁄ {Total number of affair} = 3 / 36 = 1/12.
Thus, 1/12 is the probability of rolling two dice and retrieving a sum of 4.