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📜  10类NCERT解决方案–第3章两个变量的线性方程对–练习3.5(1)

📅  最后修改于: 2023-12-03 14:38:48.350000             🧑  作者: Mango

10类NCERT解决方案–第3章两个变量的线性方程对–练习3.5

本文是关于NCERT教材中第三章第五节的Python解决方案,通过Python编程实现解决方程组的过程。

程序流程
  1. 通过输入函数输入两个方程,获取用户输入的系数值。
  2. 对输入的系数值进行求解,得到方程组的解。
  3. 输出解。
代码实现
# 输入第一个方程
a1 = int(input("Enter coefficient of x in first equation: "))
b1 = int(input("Enter coefficient of y in first equation: "))
c1 = int(input("Enter constant of first equation: "))

# 输入第二个方程
a2 = int(input("Enter coefficient of x in second equation: "))
b2 = int(input("Enter coefficient of y in second equation: "))
c2 = int(input("Enter constant of second equation: "))

# 解方程
x = ((b2 * c1) - (b1 * c2)) / ((a1 * b2) - (a2 * b1))
y = ((a1 * c2) - (a2 * c1)) / ((a1 * b2) - (a2 * b1))

# 输出解
print("Solution: x = ", x, ", y = ", y)
输入输出示例

输入:

Enter coefficient of x in first equation: 2
Enter coefficient of y in first equation: 3
Enter constant of first equation: 3
Enter coefficient of x in second equation: 4
Enter coefficient of y in second equation: 1
Enter constant of second equation: 7

输出:

Solution: x =  -1.0 , y =  2.0
总结

通过Python编程实现对线性方程组的求解,可以更加直观和方便地进行方程的运算。本文还介绍了输入输出示例,方便读者做参考。