问题1.在下列情况下，使用以下公式计算以下各项的金额和复利：
(i)本金= 3000卢比，利率= 5％，时间= 2年
(ii)本金= 3000卢比，利率= 18％，时间= 2年
(iii)本金= 5000卢比，汇率=每年每卢比10帕斯，时间= 2年
(iv)本金= 2000卢比，汇率=每年每卢比4帕斯，时间= 3年
(v)本金= 12800卢比，利率= 7.5％，时间= 3年
(vi)本金= 10000卢比，利率=半年复合计算的每年20％，时间= 2年
(vii)本金= 160000卢比，利率=每年每卢比10帕塞，每半年复利一次，时间= 2年。
解决方案：
We have,
A = P (1 + R/100)n
Let us solve
(i) Given, P = Rs 3000, rate = 5%, time = 2years
A = P (1 + R/100)n
Substituting the values we have,
= 3000 (1 + 5/100)2
= 3000 (105/100)2
= Rs 3307.5
Solving for Compound Interest, we get
Compound interest (CI) = A-P = Rs 3307.5 – 3000 = Rs 307.5
(ii) Given, P = Rs 3000, rate = 18%, time = 2years
A = P (1 + R/100)n
Substituting the values we have,
= 3000 (1 + 18/100)2
= 3000 (118/100)2
= Rs 4177.2
Solving for Compound Interest, we get
Compound interest (CI) = A-P = Rs 4177.2 – 3000 = Rs 1177.2
(iii) Given, P = Rs 5000, rate = 10%, time = 2years
A = P (1 + R/100)n
Substituting the values we have,
= 5000 (1 + 10/100)2
= 5000 (110/100)2
= Rs 6050
Solving for Compound Interest, we get
Compound interest (CI) = A-P = Rs 6050 – 5000 = Rs 1050
(iv) Given, P = Rs 2000, rate = 4%, time = 3years
A = P (1 + R/100)n
Substituting the values we have,
= 2000 (1 + 4/100)3
= 2000 (104/100)3
= Rs 2249.72
Solving for Compound Interest, we get
Compound interest (CI) = A-P = Rs 2249.72 – 2000 = Rs 249.72
(v) Given, P = Rs 12800, rate = 7 ½ % = 15/2% = 7.5%, time = 3years
A = P (1 + R/100)n
= 12800 (1 + 7.5/100)3
= 12800 (107.5/100)3
= Rs 15901.4
Compound interest (CI) = A-P = Rs 15901.4 – 12800 = Rs 3101.4
(vi) Given, P = Rs 10000, rate = 20 % = 20/2 = 10% (quarterly), time = 2years = 2 × 2 = 4years
A = P (1 + R/100)n
= 10000 (1 + 10/100)4
= 10000 (110/100)4
= Rs 14641
Solving for Compound Interest, we get
Compound interest (CI) = A-P = Rs 14641 – 10000 = Rs 4641
(vii) Given, P = Rs 160000, rate = 10% = 10/2% = 5% (half-yearly), time = 2years = 2×2 = 4 quarters
A = P (1 + R/100)n
= 160000 (1 + 5/100)4
= 160000 (105/100)4
= Rs 194481
Solving for Compound Interest, we get
Compound interest (CI) = A-P = Rs 194481 – 160000 = Rs 34481
问题2。找到Rs的金额。三年后为2400，每年按20％的年利率复利。
解决方案：
Given is the following set of values,
Principal (p) = Rs 2400
Rate (r) = 20% per annum
Time (t) = 3 years
By using the formula,
A = P (1 + R/100)n
Substituting the values we have,
= 2400 (1 + 20/100)3
= 2400 (120/100)3
= Rs 4147.2
∴ Amount is Rs 4147.2
问题3.拉曼借出卢比。 16000到Rasheed，年利率为12½％。找出3年后Rasheed应付给Rahman的金额。
解决方案：
Given :
Principal (p) = Rs 16000
Rate (r) = 12 ½ % per annum = 12.5%
Time (t) = 3 years
By using the formula,
A = P (1 + R/100)n
Substituting the values we have,
= 16000 (1 + 12.5/100)3
= 16000 (112.5/100)3
= Rs 22781.25
∴ Amount is Rs 22781.25
问题4：Meera借了一笔Rs。从西塔1000年，为期两年。如果利率是每年10％的复利，请找到Meera必须偿还的金额。
解决方案：
We have,
Principal (p) = Rs 1000
Rate (r) = 10 % per annum
Time (t) = 2 years
By using the formula,
A = P (1 + R/100)n
Substituting the values we have,
= 1000 (1 + 10/100)2
= 1000 (110/100)2
= Rs 1210
∴ Amount is Rs 1210
问题5：找出复利和单利之间的区别。总计Rs。 50,000美元，每年10％，为期2年。
解决方案：
Given details are,
Principal (p) = Rs 50000
Rate (r) = 10 % per annum
Time (t) = 2 years
By using the formula,
A = P (1 + R/100)n
Substituting the values we have,
= 50000 (1 + 10/100)2
= 50000 (110/100)2
= Rs 60500
Calculating for Compound Interest, we have
CI = Rs 60500 – 50000 = Rs 10500
We know that SI = (PTR)/100 = (50000 × 10 × 2)/100 = Rs 10000
∴ Difference amount between CI and SI = 10500 – 10000 = Rs 500
问题6。阿米特借了卢比。 16000，年利率为17½％。在同一天，他以相同的利率将其借给阿舒，但每年复利一次。他在两年结束后会获得什么?
解决方案：
Given details are,
Principal (p) = Rs 16000
Rate (r) = 17 ½ % per annum = 35/2% or 17.5%
Time (t) = 2 years
Interest paid by Amit = (PTR)/100 = (16000×17.5×2)/100 = Rs 5600
Amount gained by Amit:
By using the formula,
A = P (1 + R/100)n
Substituting the values we have,
= 16000 (1 + 17.5/100)2
= 16000 (117.5/100)2
= Rs 22090
Calculating for Compound Interest, we have
CI = Rs 22090 – 16000 = Rs 6090
∴ Amit’s total gain is = Rs 6090 – 5600 = Rs 490
问题7.找出Rs的金额。 4096年期18个月，年利率为12½％，每半年复利一次。
解决方案：
Given details are,
Principal (p) = Rs 4096
Rate (r) = 12 ½ % per annum = 25/4% or 12.5/2%
Time (t) = 18 months = (18/12) × 2 = 3 half years
By using the formula,
A = P (1 + R/100)n
Substituting the given values we have,
= 4096 (1 + 12.5/2×100)3
= 4096 (212.5/200)3
= Rs 4913
∴ Amount is Rs 4913
问题8.找出Rs的金额和复利。 8000年(1.5年)，每年10％，每半年复利一次。
解决方案：
Given details are,
Principal (p) = Rs 8000
Rate (r) = 10 % per annum = 10/2% = 5% (half yearly)
Time (t) = 1 ½ years = (3/2) × 2 = 3 half years
By using the formula,
Substituting the values we have,
A = P (1 + R/100)n
= 8000 (1 + 5/100)3
= 8000 (105/100)3
= Rs 9261
Calculating for Compound Interest, we have
∴ CI = Rs 9261 – 8000 = Rs 1261
问题9：Kamal借了Rs。来自LIC的57600反对她以每年12½％的政策建房。如果利息是每半年计算一次，请找出她在1½年后支付给LIC的金额。
解决方案：
Given details are,
Principal (p) = Rs 57600
Rate (r) = 12 ½ % per annum = 25/2×2% = 25/4% = 12.5/2% (half yearly)
Time (t) = 1 ½ years = (3/2) × 2 = 3 half years
By using the formula,
A = P (1 + R/100)n
Substituting the values we have,
= 57600 (1 + 12.5/2×100)3
= 57600 (212.5/200)3
= Rs 69089.06
∴ Amount is Rs 69089.06
问题10：艾卜哈(Abha)以信用方式从Avas Parishad买了房子。如果房子的成本是卢比。 64000，年利率为5％，每半年复利一次，找到Abha一年半后支付的利息。
解决方案：
Given details are,
Principal (p) = Rs 64000
Rate (r) = 5 % per annum = 5/2% (half yearly)
Time (t) = 1 ½ years = (3/2) × 2 = 3 half years
By using the formula,
A = P (1 + R/100)n
Substituting the values we have,
= 64000 (1 + 5/2×100)3
= 64000 (205/200)3
= Rs 68921
Calculating for Compound Interest, we have
∴ CI = Rs 68921 – 64000 = Rs 4921