问题1.平行四边形的两个相反角度是(3x – 2)°和(50 – x) ° 。找到平行四边形的每个角度的度量。
解决方案:
Given: Two opposite angles of a parallelogram are (3x – 2)° and (50 – x)°.
(3x – 2)°= (50 – x)° [Opposite sides of a parallelogram are equal]
3x + x = 50 + 2
4x = 52
x = 13
Angle x is 13°
(3x – 2) = (3*13 – 2) = 37°
(50 – x)° = (50 – 13)°= 37°
x + 37°= 180° [Adjacent angles of a parallelogram are supplementary]
x = 180°− 37°= 143°
Hence, required angles are : 37°, 143°, 37°, 143°.
问题2.如果平行四边形的角度是其相邻角度的三分之二,请找出平行四边形的角度。
解决方案:
Let the measure of the angle be x.
Therefore, the measure of the angle adjacent is 2x/3
Hence, x + 2x/3 = 180° [Consecutive angles of a parallelogram are supplementary]
2x + 3x = 540°
5x = 540°
x = 108°
Now,
⟹ x + 108°= 180° [Consecutive angles of a parallelogram are supplementary]
⟹ x + 108°= 180°
⟹ x = 180°- 108°= 72°
⟹ x = 72°
required angles are180°, 72°, 180°, 72°
问题3.如果一个角度比最小角度的两倍小24° ,则求出平行四边形所有角度的度量。
解决方案:
x + 2x – 24°= 180° [Consecutive angles of a parallelogram are supplementary]
3x – 24°= 180°
3x = 108° + 24°
3x = 204°
x = 204/3 = 68°
x = 68°
Other angle of parallelogram=2x – 24°= 2*68°- 24°= 112°
required angles are 68°,112°,68°,112°
问题4.平行四边形的周长是22厘米。如果较长的边长为6.5厘米,较短的边长是多少?
解决方案:
Given: perimeter of a parallelogram is 22 cm
Let us consider the shorter side be ‘y’.
perimeter = y + 6.5 + 6.5 + x [Sum of all sides]
22 = 2(y + 6.5)
11 = y + 6.5
y = 11 – 6.5 = 4.5 cm
Hence, the measure of the shorter side = 4.5 cm
问题5.在平行四边形ABCD中,, D = 135 ° 。确定∠A和∠B的小节。
解决方案:
In a parallelogram ABCD
Given: ∠D=135°
So, ∠D + ∠C = 180° [Consecutive angles of a parallelogram are supplementary]
∠C = 180°− 135°
∠C = 45°
In a parallelogram opposite sides are equal.
∠A = ∠C = 45° [opposite sides of parallelogram are equal]
∠B = ∠D = 135°
hence, the measures of ∠A and ∠B are 45°,135°respectively.
问题6. ABCD是一个平行四边形,其中∠A= 70 ° 。计算∠B,∠C和∠D。
解决方案:
In a parallelogram ABCD
Given: ∠A = 70°
∠A + ∠B = 180° [Consecutive angles of a parallelogram are supplementary]
70°+ ∠B = 180° [given ∠A = 70°]
∠B = 180°− 70°
∠B = 110°
Now,
∠A = ∠C = 70° [opposite sides of parallelogram are equal]
∠B = ∠D = 110°
hence, the measures of ∠A and ∠B are 70°,110°respectively.
问题7.在图中,ABCD是一个平行四边形,其中∠A= 60 ° 。如果∠A和∠B的等分线在P处相遇,则证明AD = DP,PC = BC和DC = 2AD。
解决方案:
Given: ∠A = 60°
To prove: AD = DP, PC = BC and DC = 2AD
AP bisects ∠A
so, ∠DAP = ∠PAB = 30°
Now,
∠A + ∠B = 180° [Consecutive angles of a parallelogram are supplementary]
∠B + 60°= 180°
∠B = 180°− 60°
∠B = 120°
BP bisects ∠B
so, ∠PBA = ∠PBC = 60°
∠PAB = ∠APD = 30°[Alternate interior angles]
Therefore, AD = DP [Sides opposite to equal angles are in equal length]
Similarly
∠PBA = ∠BPC = 60° [Alternate interior angles]
Therefore, PC = BC
DC = DP + PC
DC = AD + BC [ DP = AD and PC = BC ]
DC = 2AD [Since, AD = BC, The opposite sides of parallelogram are parallel and congruent]
hence proved.
问题8.在图中,ABCD是一个平行四边形,其中∠DAB= 75 °和∠DBC= 60 ° 。计算∠CDB和∠ADB。
解决方案:
Given: ∠DAB = 75°and ∠DBC = 60°
To find ∠CDB and ∠ADB
∠CBD = ∠ADB = 60° [Alternate interior angle. AD∥ BC and BD is the transversal]
InBDA
∠DAB + ∠ADB + ∠ABD = 180° [Angle sum property]
75°+ 60°+ ∠CDB = 180°
∠ABD = 180°− (135°)
∠ABD = 45°
∠ABD = ∠CDB = 45° [Alternate interior angle. AD∥ BC and BD is the transversal]
Hence, ∠CDB = 45°, ∠ADB = 60°
问题9.在图中,ABCD是平行四边形,E是BC边的中点。如果生产时的DE和AB在F处相遇,则证明AF = 2AB。
解决方案:
Given: ABCD is a parallelogram and E is the mid-point of side BC.
To prove: AF = 2AB.
Now,
In ΔBEF and ΔCED
∠BEF = ∠CED [Verified opposite angle]
BE = CE [Since, E is the mid-point of BC]
∠EBF = ∠ECD [Since, Alternate interior angles are equal]
ΔBEF ≅ ΔCED [ASA congruence]
BF = CD [Corresponding Parts of Congruent Triangle]
AF = AB + AF
AF = AB + CD [BF = CD by Corresponding Parts of Congruent Triangle ]
AF = AB + AB [CD=AB, The opposite sides of parallelogram are parallel and congruent]
AF = 2AB.
Hence proved.
问题10.以下哪个陈述是正确的(T),哪些是错误的(F)?
(i)在平行四边形中,对角线是相等的。
(ii)在平行四边形中,对角线一分为二。
(iii)在平行四边形中,对角线彼此成直角相交。
(iv)在任何四边形中,如果一对相对的边相等,则为平行四边形。
(v)如果四边形的所有角度均相等,则为平行四边形。
(vi)如果四边形的三个边相等,则为平行四边形。
(vii)如果四边形的三个角度相等,则为平行四边形。
(viii)如果四边形的所有边均相等,则为平行四边形。
解决方案:
(i) False
(ii) True
(iii) False
(iv) False
(v) True
(vi) False
(vii) False
(viii) True